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4 years ago

5

F(x) = 4^x-1; find f(3)

2 answers:

charle [14.2K]4 years ago

6 0

Answer:

f(3) = 63

Step-by-step explanation:

f(x) = 4^x-1;

Let x =3

f(3) = 4^3 -1

= 64-1

=63

ElenaW [278]4 years ago

3 0

Answer:

f(3)=16

Step-by-step explanation:

This question asks us to find f(3). We have to find what f(x), or y is, when x is equal to 3.

f(x)=4^x-1

Substitute 3 in for x.

f(3)=4^3-1

First, subtract what is in the exponents.

f(3)=4^2

4^2 is the same as multiplying 4, 2 times.

4^2=4*4=16

f(3)=16

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3 years ago

Help me please i jave 10 min left HELP

yaroslaw [1]

Answer:

Option (A).

Step-by-step explanation:

$8\frac{4}{5}$ is a mixed fraction and can be written as,

$8\frac{4}{5}=8+\frac{4}{5}$ [Combination of a whole number and a fraction]

When we multiply this mixed fraction by 7,

$7\times 8\frac{4}{5}=7\times (8+\frac{4}{5})$

$=(7\times 8)+(7\times \frac{4}{5})$ [Distributive property → a(b + c) = a×b + a×c]

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$=56+5+\frac{3}{5}$

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7 0

3 years ago

D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

3 years ago