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malfutka [58]
3 years ago
14

Suppose the block factory has only boxes and stacks. How can it pack the order for 2,410 blocks?

Mathematics
1 answer:
makvit [3.9K]3 years ago
8 0
Imagine that 1 box = 1000 blocks.

It'll be 2 boxes, 4 cases, 1 stack, and 0 single blocks.
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A library has an initial late fee of $0.50 cents and charges an additional $0.05 per day. What is the rate of change?
astraxan [27]

Answer:

Rate = \$0.05

Step-by-step explanation:

Given

Base\ Amount = \$0.50

Additional = \$0.05

Required

Determine the rate of change.

From the given parameters, we understand that the on a daily basis, there's a charge of $0.05.

This charge represent the rates at which the fee changes on a daily basis.

Hence:

Rate = \$0.05

8 0
3 years ago
A bag of tokens contains 9 red, 6 green, and 5​ blue tokens. What is the probability that a randomly selected token is red and g
german

Answer:

27/200

Step-by-step explanation:

Knowing that:

A bag of tokens contains 9 red, 6 green, and 5​ blue tokens. What is the probability that a randomly selected token is red and green?

Solve:

and = multiply

Total = 9 red + 6 green + 5 blue = 9 + 6 + 5 = 20

Total = 20 token

Thus,

There are 9 red and 6 green..

Hence,

9 out of 20 is red

6 out of 20 is green

Equation

9/20 × 6/20

Multiply Across:

9 × 6 = 54

20 × 20 = 400

54/400

Simplify

27/200

Therefore, the probability that a randomly selected token is red and green is 27/200.

<u><em>~Lenvy~</em></u>

6 0
2 years ago
Read 2 more answers
Use a calculator to solve for xin the equation 2e^3x = 400. Round your answer to<br> three decimals.
Paul [167]

the answer is

D. 1.766
3 0
4 years ago
A community bird-watching society makes and sells simple bird feeders to raise money for its conservation activities. The materi
valentina_108 [34]

Answer:

N(x) = 40 - 2x

P(x) = -2x² + 52 x - 240

maximum profit = 13

Step-by-step explanation:

given data

feeder cost = $6

average sell = 20 per week

price = $10 each

solution

we consider here price per feeder = x

and profit per feeder  id here formula   = x - 6

so that here

total profit will be

P (x)  = ( x - 6 ) Nx

here N(x) is number of feeders sold at price =  x

so formula for N (x)  is here

N(x) = 20 - 2 ( x - 10 )    

N(x) = 40 - 2x

so that

P(x) = (x-6) ( 40 - 2x)

P(x) = -2x² + 52 x - 240

since here

a = -2

b = 52

c = -240

a < 0

so quadratic function have maximum value of c - \frac{b^2}{4a}

so it will be

maximum value = -240 - \frac{52^2}{4(-2)}

maximum value = 98

so here maximum profit attained at

x = \frac{-b}{2a}

x = \frac{-52}{2(-2)}

x = 13

maximum profit = 13

3 0
4 years ago
How many solutions does this nonlinear system of equations have?
Arlecino [84]

Answer:

<h2>              One</h2>

Step-by-step explanation:

One common point of the graphs means one solution.

7 0
3 years ago
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