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3 years ago

If a right triangle has a hypotenuse of 12 cm and one leg that measures 9 cm, find the length of the other leg.

Mathematics

1 answer:

otez555 [7]3 years ago

6 0

By Pythagoras Theorem,
the length of the other leg= (12^2-9^2)^1/2
hope this helps

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Two students, Abby and Any have the same number of chocolates. Abby has one full tub of chocolates and 21 remaining chocolates.

aalyn [17]

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3 years ago

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3 years ago

A new cell phone is on sale for 40% off its original price. The sale price is $48.

Yakvenalex [24]

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3 years ago

A pet store sells goldfish and hermit crabs,

Elis [28]

Answer:

$Cost = \$28$

Step-by-step explanation:

Given

Represent Goldfish with g and hermit crabs with h.

The first statement, we have:

$7g + 3h = 26$

The second statement, we have:

$4g + 5h = 28$

Required

Determine the selling price of 6 goldfish and 4 hermit crabs

The equations are:

$7g + 3h = 26$ --- (1)

$4g + 5h = 28$ --- (2)

Make g the subject in (2)

$4g + 5h = 28$

$4g = 28 - 5h$

Divide both sides by 4

$g = \frac{1}{4}(28 - 5h)$

Substitute $\frac{1}{4}(28 - 5h)$ for g in (1)

$7g + 3h = 26$

$7(\frac{1}{4}(28 - 5h)) + 3h = 26$

$\frac{7}{4}(28 - 5h) + 3h = 26$

Multiply through by 4

$4 * \frac{7}{4}(28 - 5h) + 4*3h = 26*4$

$7(28 - 5h) + 4*3h = 26*4$

Open bracket

$196 - 35h + 12h = 104$

$196 -23h = 104$

Collect Like Terms

$-23h = 104-196$

$-23h = -92$

Make h the subject

$h = \frac{-92}{-23}$

$h = \frac{92}{23}$

$h = 4$

Substitute 4 for h in $g = \frac{1}{4}(28 - 5h)$

$g = \frac{1}{4}(28 - 5*4)$

$g = \frac{1}{4}(28 - 20)$

$g = \frac{1}{4}(8)$

$g = 2$

This implies that:

1 goldfish = $2

1 hermit crab = $4

The cost of 6 goldfish and 4 hermit crabs is:

$Cost = 6g + 4h$

$Cost = 6*\$2 + 4*\$4$

$Cost = \$12 + \$16$

$Cost = \$28$

5 0

3 years ago

A board 1.2 m long is cut into two so that the length of the longer piece is 15cm longer than twice the length of the shortest p

MAXImum [283]

Answer:

The length of the shorter piece=0.35 m

Step-by-step explanation:

Let the lengths be as follow;

Shorter piece=x

Longer piece=15 cm longer than twice shorter piece(x)

Since 1 m=100 cm, 15 cm=15/100=0.15 m

Longer piece= (2×x)+0.15=2x+0.15

Total length=1.2 m

Total length=shorter piece+longer piece

Replacing;

1.2=x+2x+0.15

3x=1.2-0.15

3x=1.05

x=(1.05/3)=0.35

The length of the shorter piece=x=0.35

4 0

3 years ago