I'll do a similar problem, and I challenge you to do this on your own using similar methods!
x+5y+2z=23
8x+4y+3z=12
9x-3y-7z=-10
Multiplying the first equation by -8 and adding it to the second one (to get rid of the x) and also multiplying the first equation by -9 and adding the third one to get rid of the x there too, we end up with
-36y-13z=-92
and
-48y-25z=-217
Multiplying both equations by -1, we get
36y+13z=-92
48y+25z=217
Multiplying the (new) first equation by -4/3 and adding it to the second (to get rid of the y), we get
(7+2/3)z=94+1/3
Dividing both sides by (7+2/3) to separate the z, we get
z=

Plugging that into
48y+25z=217, we can subtract 25z from both sides and divide by 48 to get

Lastly, we plug this into x+5y+2z=23 to get
x=23-5y-2z by subtracting 5y+2z from both sides to get
Good luck, and feel free to ask with any questions!
Answer: it’s the 3rd one
Step-by-step explanation:
Answer:
Step-by-step explanation:
As each step has the same depth and rise, they are respectively 1.2/4=0.3m and 1.8/4=0.45m.
Dividing the steps along the dotted lines, the total rise of the 4 concrete steps = (1+2+3+4)*0.45
= 4.5m
Total concrete volume = total rise * depth * width
= 4.5*0.3*1.8
= 2.43m^3
Answer: the slope is -1/15 and it means that the distance from home decreases 1/15 units per minute of walk, which indicates the your are going home.
Explanation:
The equation d = 4 - (1/5)t has these features:
- it is a linear (first degree) equation/
- d is the dependent variable, distance from home.
- t is the independent variable, minutes of walk
- 4 is the constant term and it is the value of d when t = 0, which means that it is the vertical axis intercept and represents the initial distance from home.
- - ( 1/15) is the coefficient of the independent variable, it is the slope of the equation, and means the rate of change of the distance per minute of walk.
- this slope, since it is negative, means that the distance decreases as times goes on. It means that each minute of walk the distance decreases 1/15 unit.
- you can find when the distance is zero, by doing the variable d = 0:
d = 0 = 4 - (1/15)t ⇒ t = 4×15 = 60 min.
The given equation, d = 4 - (1/5)t is a linear equation, whose y-intercept form is y = mx + b.
- m is the slope, therefore it is - 1/15.
- 4 is the y-intercept, therefore it is 4.
The domain of the function is the interval [0, 60], meaning that those are the minutes of the walk.
The range of the function is the interval [4, 0] meaning that the distance goes from 4 to 0 units.
You have plenty information to do the graph:
- label the horizontal axis t in minutes
- do marks at 0, 5, 10, 15, 20, 25, .... up to 60 on the horizontal axis
- lable the vertical axis d
- do marks at 4, 3, 2, 1, on the vertical axis
- draw the points (0, 4) and (60,0)
- draw a segment joining those two points.
You can see the graph in the image attached.