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3 years ago

Find the 9th partial sum of the geometric sequence an=43n–1.

Mathematics

1 answer:

siniylev [52]3 years ago

7 0

Answer:

39364.

Step-by-step explanation:

I guess its an = 4*(3)^(n-1)

r = 3, a1 = 4 and n = 9

Sum of n terms = a1 * (r^n - 1) / (r - 1)

so S9 = 4 *(3^9 - 1) / (3 - 1)

= 4 * (19683 - 1) / 2

= 78728/2

= 39364.

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3 years ago

How to solve 10x+36-38x-47

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3 years ago

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Please help me with NUMBER 7 !! Thank you so much! 20 points!! :))

mart [117]

Answer:

x<-3 or x>-1

Step by step explanation:

Start with -5x>15. To get x by itself, we have to divide each side by -5. When we do that we get x<-3. (Don't forget to flip the sign when dealing with negative · and ÷.) Now answer the second equation. x-5>-6 To get x by itself, add 5 to both sides to get x>-1. Now we have x<3 or x>-1.

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3 years ago

One container holds 1 1/7 quarts of water and second container holds 5 3/4 quarts of water how many more harts of water does the

Anna007 [38]

Answer:

129/28 (4.6 approx.)

Step-by-step explanation:

The first hols 1 1/7 quarts, it is: 1 + 1/7

Using 7 as common denominator and summing:

1 + 1/7 = 7/7 + 1/7 = 8/7

The second holds 5 3/4 which is: 5 + 3/4. Using 4 as common denominator:

5 + 3/4 = 20/4 + 3/4 = 23/4

Now we need to know how much greater is 23/4 than 8/7. For comparing them we need to set them to a common denominator. The easiest way is use a number that is multiple of both, 4 and 7, lets us 28. We need to multiply the numerators by the number that, multiplied by denominators gives us 28. For the first is 4, and for the second 7.

8/7 = (8*4)/7*4=32/28

23/4= (23*7)/4*7 = 161/28

Now, we only have to subtract:

23/4 - 8/7 = 161/28 - 32/28 = 129/28

So, the second container has 129/28 more quarts of water (approx. 4.60) than the first.

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4 years ago