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meriva
3 years ago
13

Find the 9th partial sum of the geometric sequence an=43n–1.

Mathematics
1 answer:
siniylev [52]3 years ago
7 0

Answer:

39364.

Step-by-step explanation:

I guess its an = 4*(3)^(n-1)

r = 3, a1 = 4 and n = 9

Sum of n terms = a1 * (r^n - 1) / (r - 1)

so S9 = 4 *(3^9 - 1) / (3 - 1)

= 4 * (19683  - 1) / 2

= 78728/2

= 39364.

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Mrs. Jacobs is making several batches of cookies and is using 84 total ounces of chips. The cookies have chocolate chips and pea
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The ounces of chocolate chips used by Mrs Jacob is 70 ounce

<em><u>Solution:</u></em>

Given that Jacob is making several batches of cookies and is using 84 total ounces of chips

Let "c" be the ounces of chocolate chips

Let "p" be the ounces of peanut butter chips

To find: ounces of chocolate chips used by Mrs Jacob

Given that There are 5 times as many ounces of chocolate chips as peanut butter chips

<em><u>Thus we can frame a equation as:</u></em>

ounces of chocolate chips = 5 x ounces of peanut butter chips

c = 5p -------- eqn 1

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ounces of chocolate chips + ounces of peanut butter chips = 84

c + p = 84 ---- eqn 2

Substitute eqn 1 in eqn 2

5p + p = 84

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<h3>p = 14</h3>

Substitute p = 14 in eqn 1

c = 5(14) = 70

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4 years ago
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