Answer:
30 m
Step-by-step explanation:
You simply add the lengths of all the sides. 3 m is not needed for this.
Answer: it increased by $403. He ended with $6603
Step-by-step explanation: since he started off with $6200, you would move the decimal over two places (.065) and then multiply 6200 and .065 to get $403.
A=1/3h(b1-b2). So h=3/(b1-b2)
The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
<h3>What is the approximation about?</h3>
From the question:
Mars: F(x) = 2/3
Therefore, If x = 15
Then:
f (15) = 2/3 ![\sqrt[8]{15}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B15%7D)
= 16/3
= 20.7ft/s
Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.
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Answer:
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Step-by-step explanation:
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(p.s. I just saw your profile and most of the questions include pictures, on my end, it says that these pics are blocked. So, try asking the question without having to take a picture, instead, just type the question out. (and include the choices, if there are any))