Answer:
32760 different schedules are possible.
Step-by-step explanation:
The order is important.
For example
Prague on Monday, Berlin on Tuesday, Liverpool on Wednesday and Athens on Thursday is a different schedule than Berlin on Monday, Prague on Tuesday, Liverpool on Wednesday and Athens on Thursday.
So we use the permutations formula to solve this question.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:
How many different schedules are possible?
Choose 4 cities among a set of 15. So
32760 different schedules are possible.
If 2 + 5i is a zero, then by the complex conjugate root theorem, we must have its conjugate as a zero to have a polynomial containing real coefficients. Therefore, the zeros are -3, 2 + 5i, and 2 - 5i. We have three zeros so this is a degree 3 polynomial (n = 3).
f(x) has the equation
f(x) = (x+3)(x - (2 + 5i))(x - (2 - 5i))
If we expand this polynomial out, we get the simplest standard form
f(x) = x^3-x^2+17x+87
Therefore the answer to this question is f(x) = x^3-x^2+17x+87
4*-5 is -20 is does not equal -25 so it’s false
It's 26×10×10×10 because there are 26 possibilities (a-z) for the first letter and 10 possibilities (0-9) for each number. That makes the answer 26,000.
Answer:
120
Step-by-step explanation:
180(6-2)/6
