The maximum value of the objective function is 31.787
<h3>How to maximize the function?</h3>
The given parameters are:
Objective function:
Max P = 4x + 5y + 21
Subject to:
y- x < 1
21x + 7y < 25
x>-2, y>-4
Rewrite the inequalities as equation
y - x = 1
21x + 7y = 25
Add x to both sides in y - x = 1
y = x + 1
Substitute y = x + 1 in 21x + 7y = 25
21x + 7x + 7 = 25
Evaluate the like terms
28x = 18
Divide both sides by 28
x = 0.643
Substitute x = 0.643 in y = x + 1
y = 0.643 + 1
y = 1.643
So, we have:
Max P = 4x + 5y + 21
This gives
P = 4 * 0.643 + 5* 1.643 + 21
Evaluate
P = 31.787
Hence, the maximum value of the objective function is 31.787
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Answer:
Step-by-step explanation:
2, -3 , -8 , -13 , - 18 .............
This is an arithmetic sequence.
First term = a = 2
Common difference = Second term - first term
= -3 - 2 = -5
Nth term = a + (n - 1)*d
= 2 + (n - 1)*(-5)
= 2 + n*(-5) - 1 *(-5)
= 2 - 5n + 5
= 7 - 5n
n = 19,
19th term = 7 - 5*19
= 7 - 95
= - 88
n = 21,
21st term = 7 - 5*21
= 7 - 105
= -98
A) 9 + 3x + 6 + 9x + 5
b) 12x + 20
