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Lapatulllka [165]

3 years ago

15

Help help me help me help me

1 answer:

elena-s [515]3 years ago

5 0

Answer:

Step-by-step explanation:

Basically your gonna break up both numbers into smaller numbers and add them to get the same answer

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what is the volume of a rectangular prism that has a length of 8.5 centimeters (cm), a width of 3.2 centimeters, and a height of

Yuki888 [10]

Answer:

The volume of the rectangular prism is $163.2cm^3$

Step-by-step explanation:

A rectangular prism is in the shape of cuboid which has three dimensions i.e Length, width and height.

Given: Length =8.5 cm width= 3.2 cm and Height= 6 cm

The volume of a Cuboid = $Length*Width*Height$

Applying the given dimensions in the formula:

The volume of a Cuboid= $8.5cm*3.2cm*6cm$

= $163.2cm^3$

The volume of the rectangular prism is $163.2cm^3$

3 0

2 years ago

Label the horizontal and vertical sides of the triangle with expressions representing their length.

Alex Ar [27]

Answer:

What is the triangle cant give answer without pic of triangle

Step-by-step explanation:

Impossible to answer without anything shown

8 0

2 years ago

A farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. Find the maximum area he can close.

Margarita [4]

Answer:

Width of 37.5 feet and length of 50 feet will maximize the area.

Step-by-step explanation:

Let w represent width and l represent length of the pen.

We have been given that a farmer has 300 ft of fence to enclose 2 adjacent rectangular pens bordering his barn. We are asked to find the dimensions that will maximize the area.

We can see from the attachment that the perimeter of the pens would be $4w+3l$ .

We can set our given information in an equation $4w+3l=300$ .

The area of the two pens would be $A=2l\cdot w$ .

From perimeter equation, we will get:

$w=\frac{300-3l}{4}$

Substituting this value in area equation, we will get:

$A=2l\cdot (\frac{300-3l}{4})$

Since we need to maximize area, so we need to find derivative of area function as:

$A=\frac{600l-6l^2}{4}$

Bring out the constant:

$A=\frac{1}{4}*\frac{d}{dl}(600l-6l^2)$

$A=\frac{1}{4}*(600-12l)$

$A=150-3l$

Now, we will set our derivative equal to 0 as:

$150-3l=0$

$150=3l$

$\frac{150}{3}=\frac{3l}{3}$

$50=l$

Now, we will substitute $l=50$ in equation $w=\frac{300-3l}{4}$ to solve for width as:

$w=\frac{300-3(50)}{4}$

$w=\frac{300-150}{4}$

$w=\frac{150}{4}$

$w=37.5$

Therefore, width of 37.5 feet and length of 50 feet will maximize the area.

8 0

3 years ago

Help me please with this

AysviL [449]

Since both angle are congruent (equal/same), which means that both side is equal to 40 degrees, we will put the equation like this:

5x - 5 = 40

Now we’ll solve for x:

5x - 5 = 40
+ 5 + 5 (Add 5 to both sides)

5x = 45
—- —— (Five both side by 5)
5 5

x = 9

Now we left with x, so x is equal to 9.

8 0

3 years ago

Find the area of the shaded region

Setler79 [48]

Answer:

I would help you and say the answer but..

Step-by-step explanation:

I dont know what it is :c

7 0

2 years ago