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Maru [420]
3 years ago
8

Which graph represents the solution set of system of inequalities?

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
7 0

Answer:

The first graph <em>(picture of the graph attached)</em>

Step-by-step explanation:

We have two inequalities:

<em>3y ≥ x-9</em>

<em>3x+y > -3</em>

We have to see which graph represents the solution to these inequalities.

We are going to solve for some values of x:

<em>First inequality 3y ≥ x-9</em>

y ≥ (x-9) / 3

If we give values to x then we solve for y:

<em>x             y</em>

<em>-2            -3.67</em>

<em>0             -3</em>

<em>2              -2.34</em>

<em>4              1-67</em>

With these values, we can graph the first line, which is continuous because the inequality has <em>≥ </em>

And because it is greater or equal to the shaded region is everything up from the line.

The second inequality <em>3x+y > -3</em>

<em>y > -3 - 3x</em>

<em>x            y</em>

<em>-4           9</em>

<em>-2           3</em>

<em>0            -3</em>

Now we can graph the second inequality which will be a continuous line because it only has <em>></em>

The shaded region has to be up from the line because it is greater than.

Elis [28]3 years ago
5 0

3y\geqx-9\qquad|:3\\\\y\geq\dfrac{1}{3}x-3\\\\3x+y > -3\qquad|-3x\\\\y > -3x-3

\left\{\begin{array}{ccc}y\geq\dfrac{1}{3}x-3\\\\y > -3x-3\end{array}\right


y=\dfrac{1}{3}x-3\\\\for\ x=0\to y=\dfrac{1}{3}(0)-3=-3\to(0,\ -3)\\\\for\ x=3\to y=\dfrac{1}{3}(3)-3=1-3=-2\to(3,\ -2)\\\\y=-3x-3\\\\for\ x=0\to y=-3(0)-3=-3\to(0,\ -3)\\\\for\ x=-1\to y=-3(-1)-3=3-3=0\to(-1,\ 0)

y\geq\dfrac{1}{3}x-3

solid line. we shade above the line

y > -3x-3

the dotted line. shadow above the line

Answer in the attachment (the first graph).

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