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nika2105 [10]
3 years ago
13

Both Dale and Chan went running for an hour. Dale ran 5 miles and Chan ran 2.5 miles. How did Dale’s distance compare to Chan’s?

(Use division to compare.)
Mathematics
2 answers:
Paraphin [41]3 years ago
8 0
Dale = 5 miles
Chan = 2.5 miles
 5 ÷ 2.5 = 2
Dale ran twice as fast as Chan
natali 33 [55]3 years ago
3 0

In the given hour, Dale ran 5 miles and Chan ran 2.5 miles.

Let Dale's running miles be represented by the variable D and let Chan's running miles be represented by the variable C.

In-order to compare Dale's running miles to Chan's by using division we get:

\frac{D}{C}=\frac{5}{2.5} = \frac{2}{1}

D=2C

Thus, Dale ran twice the distance Chan ran in the same amount of time of 1 hour.

Equivalently we can say that Chan ran half the distance Dale ran in the same amount of time of 1 hour.


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cupoosta [38]

Answer:

3/5 or 0.6

Step-by-step explanation:

Here, given the value of tan theta , we want to find the value of sine theta

Mathematically;

tan theta = 0pposite/adjacent

Sine theta = opposite/hypotenuse

Firstly we need the length of the hypotenuse

This can be obtained using the Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides.

Let’s call the hypotenuse h

h^2 = 3^2 + 4^2

h^2 = 9 + 16

h^2 = 25

h = √(25)

h = 5

Now from the tan theta, we know that the opposite is 3

Thus, the value of the sine theta = 3/5 or simply 0.6

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Step-by-step explanation:

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