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3 years ago

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For the graph x = 1 find the slope of a line that is perpendicular to it and the slope of a line parallel to it. Explain your an

swer with two or more sentences.

1 answer:

andriy [413]3 years ago

8 0

Answer:

perpendicular : y = 1

x = 1 is a vertical line infinitely long at x = 1. so, we also know that y = 1 is a horizontal line at y = 1. Hence, they are parallel

parallel : x = 2

since x = 1 is a vertical line at x = 1, we can get another vertical line at the x- axis, which will be parallel to the given line. hence, x = 2 is a vertical line at x = 2, as it is at a distance of 2 units from the initial line no matter where, x = 2 is parallel to x = 1

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Three trucks delivered potatoes to a warehouse. The first truck delivered 5 7/8 tons of potatoes, the second one 6 1/2 tons more

mina [271]

Answer:

12 5/8 tons were delivered by the third truck

Step-by-step explanation:

25 = 6 4/8 + 5 7/8 + x

25 = 12 3/8 + x

- 12 3/8

12 5/8 = x

6 0

3 years ago

Read 2 more answers

Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)(t^2-2t+2)\,\mathrm dt$

Complete the square in the quadratic term of the integrand: $t^2-2t+2=(t-1)^2+1=(1-t)^2+1$ , then in the integral we substitute $u=1-t$ :

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt$

$\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du$

Make another substitution of $v=u^2$ :

$\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv$

Integrate by parts, taking

$r=v+1\implies\mathrm dr=\mathrm dv$

$\mathrm ds=e^v\,\mathrm dv\implies s=e^v$

$\displaystyle=-e^v(v+1)\bigg|_{v=0}^{v=1}+\int_{v=0}^{v=1}e^v\,\mathrm dv$

$\displaystyle=-(2e-1)+(e-1)=-e$

So, we have by the fundamental theorem of calculus that

$\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)$

$\implies-e=f(1,1,1)-2$

$\implies f(1,1,1)=2-e$

3 0

3 years ago

Help please !!!!!!!!!!!!!!

DIA [1.3K]

The LCM will be the values that are common to both factors. From the given values the LCM will be 2² * 3² * 5

<h3>Least common multiple</h3>

LCM is the lowest number that can divide all other numbers given in an expression.

Given the prime factorizations 2² * 3² * 5 and 2*3*5. The LCM will be the values that are common to both factors.

From the given values the LCM will be 2² * 3² * 5

Learn more on LCM here: brainly.com/question/233244

#SPJ1

8 0

2 years ago

Which sentence represents the inequality -2b + 7 > 27.5?<br> Help PLEASE!

AVprozaik [17]

-2b + 7 > 27.5
- 2b > 27.5 - 7
- 2b > 20.5
b < - 10.25

7 0

3 years ago

Read 2 more answers

Look at the two 2s in this number:

Reika [66]

Answer:

The blue 2 on the left is 10 times the value of the orange 2 on the right.

Step-by-step explanation:

3 0

3 years ago