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Black_prince [1.1K]
2 years ago
7

Faris wrote this equation to represent a real-world situation.

Mathematics
1 answer:
user100 [1]2 years ago
8 0
There was a tree that had 6 times a apples on it. 16 apples were rotten. If b=how many apples are still on the tree, then how many apples are left?
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How do you solve this step by step? “ I’m thinking of a number. If you multiply it by 6 and then add 7, you will get 55. What is
lozanna [386]

Answer:

8

Step-by-step explanation:

55 -7 = 48

48/6= 8

Check answer:

8x6= 48

48+7= 55

5 0
3 years ago
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When it says graph the image, it's asking me to graph a reflection across x = -2. what's the answer look like?
uranmaximum [27]

The reflection across x = -2 will be x = 2.

8 0
3 years ago
Bethany, Lauren, Amanda, and David all meet at a family reunion. They are comparing their ages. They have found that Lauren is 1
tekilochka [14]
Lauren =l
David=d
Bethany's =x
Amanda =y
l=x+13
d=y+11
lx=2y
<span>(x+13)x=2y
</span>2y=x^2+13x
y= \frac{1}{2}(x^2+13x)
or
y= \frac{x^2}{2}+ \frac{13}{2}x
(x-20)(l-20)=d
<span>(x-20)(x+13-20)=y+11 </span><span>
</span>y+11=(x-20)(x-7)
y+11=x^2-27x+140
y=x^2-27x+129
so I believe its b
Hope this helps :)
6 0
3 years ago
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The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
Tomen puntos <br>toy aburridoooo​
ivanzaharov [21]

Answer:

aww thank you

pls mark brainliest

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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