Answer:
i think it would be a bit to the left of 9
Answer:
For a circle of radius R, the circumference is:
C = 2*pi*R
where pi = 3.14
And if we have an arc defined by an angle θ, the length of the arc is:
A = (θ/360°)*2*pi*R
Here we can not see the image, then i assume that B is the angle that defines the arc AC.
Now we know that the circumference is 120 in, then:
2*pi*R = 120in
Then the length of the arc is:
A = (θ/360°)*120 in
Then if the angle is 18°, we have:
A = (18°/360)*120 in = 6in
The average rate of change from x = -1 to x = 2 is 2
<u>Solution:</u>
Given function is:
f(x) = 2x - 1
We have to find the average rate of change from x = -1 to x = 2
<em><u>The average rate of change is given as:</u></em>

<em><u>The average rate of change from x = -1 to x = 2 is given by formula:</u></em>

<em><u>Find f(2) and f( - 1)</u></em>
<em><u>Substitute x = 2 in given function</u></em>
f(2) = 2(2) - 1 = 4 - 1 = 3
<em><u>Substitute x = -1 in given function</u></em>
f( - 1) = 2(-1) - 1 = -2 - 1 = -3
<em><u>Substitute the values in above formula,</u></em>

Thus average rate of change from x = -1 to x = 2 is 2
7.43: Let
denote the random variable for height and
for the sample mean. Then if
is the mean of
So the probability that the difference between the sample and population means does not exceed 0.5 inch is

per the empirical or 68/95/99.7 rule.
7.44: For a sample of size <em>n</em>, the sample standard deviation would be
. We want to find <em>n</em> such that

Comparing to the equation from the previous part, this means we would need

so a sample of at least 157 men would be sufficient.
Anna= a
Vickie= v
Luanna= l
a is 3 years older that v
l is 2 years younger than v
Anna's age; 3+v
Luanna's age; v-2