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anastassius [24]
4 years ago
8

Erin is pouring cake batter into a pan. The pan she is using is 8 inches wide,

Mathematics
1 answer:
sergey [27]4 years ago
3 0

Answer:

242.52 cubic inches

Step-by-step explanation:

Volume of the cake pan = Length × Width × Height

From the about question, we have the following dimensions for the cake pan

8 inches wide = Width

11 inches long = Length

7 cm deep = Height

We are asked to find the maximum volume in inches. Hence all the dimensions have to be in inches.

Converting Height in cm to inches

From the question,

2.54 cm = 1 inch

7cm = x inch

Cross Multiply

2.54 × x = 7 × 1

x = 7/2.54

x = 2.7559055118 inches

Volume of the cake pan =

8 × 11 × 2.7559055118

= 242.51968504 cubic inches

Approximately, the volume of the cake pan = 242.52 cubic inches

What is the maximum volume, in cubic

inches, the cake pan can hold is 242.52 cubic inches

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Answer: The credit card will paid off within 10 years, therefore the correct option is D.

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Equation of the circle is (x+6)^{2}+(y+10)^{2}=20.

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$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

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To calculate the radius using distance formula.

r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

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r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}

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(x-a)^{2}+(y-b)^{2}=r^{2}, where (a, b) are center and r is the radius.

Here, center = (–6, –10) and r=\sqrt{20}

(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}

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