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melisa1 [442]
3 years ago
9

Y=3x-5 2y - 3x = 5 Solve by subsitution

Mathematics
2 answers:
m_a_m_a [10]3 years ago
6 0
\left\{\begin{array}{ccc}y=3x-5\\2y-3x=5\end{array}\right\\\\substitute\ y=3x-5\ to\ 2y-3x=5\\\\2(3x-5)-3x=5\\2\cdot3x-2\cdot5-3x=5\\6x-10-3x=5\\3x-10=5\ \ \ /+10\\3x=15\ \ \ \ /:3\\x=5\\\\

\left\{\begin{array}{ccc}x=5\\y=3x-5\end{array}\right\\\left\{\begin{array}{ccc}x=5\\y=3\cdot5-5\end{array}\right\\\left\{\begin{array}{ccc}x=5\\y=15-5\end{array}\right\\\left\{\begin{array}{ccc}x=5\\y=10\end{array}\right
Dovator [93]3 years ago
4 0


y = 3x - 5
2y - 3x = 5

2(3x - 5) - 3x = 5
6x - 10 - 3x = 5
3x - 10 = 5
3x = 15
x = 5

y = 3(5) - 5
y = 15 - 5
y = 10

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