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Reika [66]
3 years ago
11

You are the chief financial advisor to a corporation that owns an office complex consisting of 50 units. At $400 per month, ever

y unit can be rented. However for each $20 per month increase, there will be two vacancies with no possibility of filling them The corporation wants to receive a total of $20,240 per month from rents in the complex. You are asked to determine the rent that should be charged for each unit. What is your reply?
Mathematics
1 answer:
Alex787 [66]3 years ago
7 0
120 and 8 is the answer to the question.<span />
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I need help with this
horrorfan [7]
Filling in the table you have in the right column ...
x × 0.2 = 0.2x
y × 0.05 = 0.05y
and their total
15 × 14% = 2.1

The table tells you two equations based on the totals in the bottom row:
  x + y = 15
  0.2x + 0.05y = 2.1
There are a number of ways to solve these equations. It often works well to use substitution for mixture problems, substituting for the variable that represents the smallest contributor (y).
  0.2x + 0.05(15 - x) = 2.1
  0.15x = 1.35 . . . . . . . . simplify and subtract 0.75
  x = 9 . . . . . . . . . . . . . . divide by 0.15
  y = 15 - 9 = 6

There should be 9 gallons of 20% alcohol in the mix.
There should be 6 gallons of 5% alcohol in the mix.

_____
I like to use an X-diagram to work mixture problems. The strengths of the contributors to the mix are listed on the left, and the mixture strength is shown in the middle. The numbers on the right are the differences along the diagonals. They tell you the proportion of each contributor to the mix.

Since these proportion numbers add up to 15, the number of gallons of mix you want, each is the number of gallons of the corresponding contributor:
  9 gallons of 20%; 6 gallons of 5%.

7 0
3 years ago
A triangular prism is shown below.
Sergio [31]

Answer:

(5)(8)(14)

Step-by-step explanation:

5 0
3 years ago
The following measurements (in picocuries per liter) were recorded by a set of helium gas detectors installed in a waste disposa
Novay_Z [31]

Answer:

The 90% confidence interval is (493.1903, 550.2097), and the critical value to construct the confidence interval is 2.0150

Step-by-step explanation:

Let X be the random variable that represents a measurement of helium gas detected in the waste disposal facility. We have observed n = 6 values, \bar{x} = 521.7 and S = 31.6368. We will use  

T = \frac{\bar{X}-\mu}{S/\sqrt{n}}  

as the pivotal quantity. T has a t distribution with 5 degrees of freedom. Then, as we want a 90% confidence interval for the mean level of helium gas present in the facility, we should find the 5th quantile of the t distribution with 5 degrees of freedom, i.e., t_{5}, this value is -2.0150. Therefore the 90% confidence interval is given by

521.7\pm 2.0150(31.6368/\sqrt{5}), i.e.,

(493.1903, 550.2097)

To find the 5th quantile of the t distribution with 5 degrees of freedom, you can use a table from a book or the next instruction in the R statistical programming language

qt(0.05, df = 5)

8 0
3 years ago
Look at Picture:
Sindrei [870]

Answer:

A=A B=2A and C=3

Step-by-step explanation:

4 0
3 years ago
Help I dont get what to do
Mars2501 [29]

Answer:

  a/(bxy) if b≠0, x≠0, y≠0, x≠y

Step-by-step explanation:

You have correctly simplified the expression. The conditions placed on both the original and simplified forms are that none of the denominator factors may be zero. The denominator factors are b, x, y, and (x-y).

  \dfrac{a}{bxy}\text{ if $b\ne0;$ $x\ne0;$ $y\ne0;$ $x\ne y$}

6 0
2 years ago
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