The answer would be A. c^2 – b^2
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Taking the square root of both sides gives two possible cases,
or
Recall that
If 
and 
, we have
so in the equations above, we can write
Then in the first case,
(where 
is any integer)
and in the second,
Then the solutions that fall in the interval 
are
The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
Learn more on polynomial here: brainly.com/question/2833285
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Answer:
4 5/12
Step-by-step explanation:
Convert to mixed fraction 7/4 + 8/3
Find common denominator, 12
21/12 + 32/12
add numerators (21+32)/12 = 53/12
reduce fraction 4 5/12
No
We know scale factor(k)=y/x
Calculate units as 1 and find k
For left side
Hence its not a copy
