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Sav [38]
3 years ago
13

I need to know how to solve 5423 divided by 52 i can't seem to get an answer

Mathematics
2 answers:
kompoz [17]3 years ago
7 0
5423 ÷ 52

= \frac{5423}{52}

= 104.288461538461538 ≈ 104.29


prohojiy [21]3 years ago
3 0
5200 / 52 is 100, quite straight forward. That leaves 223 to be divided.
So 52 x (what value) is lower than 223? 52 x 4 would work, making 208, and 223 - 208 = 15.

So 5423 / 52 = (100 + 4) + (15/52) = 104 + 15/52, hope this helps.
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The midpoint, M , of segment AB has coordinates (2,−1) . If endpoint A of the segment has coordinates (−3,5) , what are the coor
lbvjy [14]

the coordinates of endpoint B are (7,7)

Answer:

Solution given:

M(x,y)=(2,-1)

A(x_{1},y_{1})=(-3,5)

Let

B(x_{2},y_{2})=(a,b)

now

by using mid point formula

x=\frac{x_{1}+x_{2}}{2}

$ubstituting value

2*2=-3+a

a=4+3

a=7

again

y=\frac{y_{1}+y_{2}}{2}

$ubstituting value

-1*2=5-b

b=5+2

b=7

the coordinates of endpoint B are (7,7)

8 0
3 years ago
7x + 2y=24<br> 8x + 2y=30
Bumek [7]

Answer:

x=6 y=-9

Step-by-step explanation:

  • Layer the equations on each other as you would in a subtraction problem:

               8x + 2y=30

               7x + 2y=24  

  • Subtract the equation just like you would normally. This should leave 1x=6 or x=6.
  • Now that you have your x value, plug it in as x for one of the equations. For the 2nd equation, this leaves:

               42+2y=24 then

               2y=-18 then

               y=-9

  • Double check your y value by plugging x=6 into the first equation. This should also leave y=-9.

3 0
3 years ago
Find all Values of b that will make the polynomial a perfect square trinomial.
weeeeeb [17]

Answer:

10,404/334,084

Step-by-step explanation:

Given the polynomial

289r^2 - 102r + c

We are to find the value of c that will make it a perfect square

Divide through by 289

289r²/289 - 102r/289 + c/289

Half of the coefficient of r is 1/2(102/289)

Half of the coefficient of r = 102/578

Square the result

r² = (102/578)²

r² = 10,404/334,084

Hence the required constant is 10,404/334,084

8 0
3 years ago
Answer the questions about the cone. V= 1/3 BH
BartSMP [9]

Answers the answer for question one is 3 , for question number two the answer is 9 and the answer for the last question is 24

Step-by-step explanation:

5 0
3 years ago
Use the discriminant to predict the nature of the solutions to the equation 4x-3x²=10. Then, solve the equation.
AleksandrR [38]

Answer:

Two imaginary solutions:

x₁= \frac{2}{3} -\frac{1}{3} i\sqrt{26}

x₂ = \frac{2}{3} +\frac{1}{3} i\sqrt{26}

Step-by-step explanation:

When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.

The discriminant gives us information on how the solutions of the equations will be.

  1. <u>If the discriminant is zero</u>, the equation will have only one solution and it will be real
  2. <u>If the discriminant is greater than zero</u>, then the equation will have two solutions and they both will be real.
  3. <u>If the discriminant is less than zero,</u> then the equation will have two imaginary solutions (in the complex numbers)

So now we will work with the equation given: 4x - 3x² = 10

First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0

So:

4x - 3x² = 10

-3x² + 4x - 10 = 0 will be our equation

with this information we have that a = -3 b = 4 c = -10

And we will find the discriminant: b^{2} -4ac = 4^{2} -4(-3)(-10) = 16-120=-104

Therefore our discriminant is less than zero and we know<u> that our equation will have two solutions in the complex numbers. </u>

To proceed to solve the equation we will use the general formula

x₁= (-b+√b²-4ac)/2a

so x₁ = \frac{-4+\sqrt{-104} }{2(-3)} \\\frac{-4+\sqrt{-104} }{-6}\\\frac{-4+2\sqrt{-26} }{-6} \\\frac{-4+2i\sqrt{26} }{-6} \\\frac{2}{3} -\frac{1}{3} i\sqrt{26}

The second solution x₂ = (-b-√b²-4ac)/2a

so x₂=\frac{-4-\sqrt{-104} }{2(-3)} \\\frac{-4-\sqrt{-104} }{-6}\\\frac{-4-2\sqrt{-26} }{-6} \\\frac{-4-2i\sqrt{26} }{-6} \\\frac{2}{3} +\frac{1}{3} i\sqrt{26}

These are our two solutions in the imaginary numbers.

7 0
3 years ago
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