Answer:
Probability that detector B goes off is '0.615'
Step-by-step explanation:
Given that:
1) Probability that detector A goes off and detector B does not go off is 0.25.
2)Probability that detector A does not go off is 0.35.
3)Probability that detector A goes off is (1-0.35)=0.65
Assuming that
Probability that detector B goes off is 'p' Hence the probability that detector B does not goes off is (1-p)
Thus the probability that detector A goes off and detector B does not go off is product of the individual probabilities
Probability that detector B goes off is '0.615'
Argument
You have a total of 8 + 9 + 3 balls = 20
The first ball is 17/20 Probability that no ball drawn is red the first time
The Second ball is 16/19 Probability that no ball drawn is red the 2nd time
The third ball is 15/18 Probability that no ball drawn is red the 3rd time
Answer
Total Probability = 17/20 * 16/19 * 15/18 = 34/57
My calculator figures out fractions. You can do this just as easily with decimals.
0.85 * 0.8421 * 0.8333333 = 0.5964
34/57 = 0.5965 which is close enough.
If you have choices, choose the one that coincides with my answer. Otherwise use the decimal value.
Answer is
<span>Multiplication Property of Equality
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hope it helps
Answer:
I think it would be C. 1/6. not for sure though
Step-by-step explanation:
