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My name is Ann [436]
3 years ago
14

Victor big 30 chocolate chip cookies, eating peanut butter cookies and 24 sugar cookies he wants to split them into equal and Id

entical bags to sell at the bake sale.what is the greatest number of bags of cookies Victor can make
Mathematics
1 answer:
romanna [79]3 years ago
3 0
The question is not clear.
I will take a guess at what you meant
You have 30 Choc Chip cookies
and 24 sugar cookies..
What is the largest divisor or factor of 30 and 24 have in common?
30 Factors (1,2,3,5,6,10,15,30)
24 Factors (1,2,3,4,6,8,12,24)
6 is the largest factor
So you can create 6 bags:
6 ×5 is 30
6×4 is 24
containing 5 Choc Chip and 4 sugar in each bag.
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Write an explicit formula for an,the Nth term of the sequence 4,12,36
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Answer:

3^{n}+3^{n-1}

Step-by-step explanation:

Since the sequence is geometric (it multiplies the previous number each time). The nth term sequence would be x^n + yn

Because the sequence multiplies by 3 each time, The base number in that equation would be 3^n +yn.

So 3^n of the equation would be:
3, 9, 27.

Compare the 2 equations:
4, 12, 36

3, 9 ,27

The difference between the 2 equations is: 1, 3, 9 which itself is a geometric sequence so the nth term of this new equation is: 3^{n-1}.

Combine these 2 equations together and you get:

3^{n}+3^{n-1}.

6 0
2 years ago
Consider a uniform distribution from aequals4 to bequals29. ​(a) Find the probability that x lies between 7 and 27. ​(b) Find th
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Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

P(c \leq x \leq d) = \frac{d - c}{b - a}

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So c = 7, d = 27

P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8

80% probability that x lies between 7 and 27.

​(b) Find the probability that x lies between 6 and 13. ​

So c = 6, d = 13

P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

​So c = 9, d = 20

P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So c = 11, d = 18

P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28

28% probability that x lies between 11 and 18.

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2 years ago
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Answer:

Step-by-step explanation:

22

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\bf f(x)=ln(x-5)\qquad [6,8]\qquad \cfrac{df}{dx}=\cfrac{1}{x-5}\\\\
-----------------------------\\\\
\textit{mean value theorem}\qquad f'(c)=\cfrac{f(b)-f(a)}{b-a}\\\\
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f'(c)=\cfrac{1}{c-5}\qquad thus\quad \cfrac{1}{c-5}=\cfrac{f(8)-f(6)}{8-6}
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\cfrac{1}{c-5}=\cfrac{ln(3)-ln(1)}{2}\implies \cfrac{1}{c-5}=\cfrac{ln(3)-0}{2}
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