Answer:
Step-by-step explanation:
Sample data
204.999 206.149 202.102 207.048 203.496 206.343 203.496 206.676 205.831
N=9
Sum, Σx: 1846.14
Mean, μ: 205.12666666667
Variance, s^2: 2.6217475555555
Std dev = s = 1.619
The sample mean follows a t distribtion with df =8
Mean difference = 205.13-204.8 = 0.50
Std error = std dev/sqrt n = 0.540
Test statistic = Mean diff/se = 0.9259
p value = 0.1907 (one tailed at 95%)
Since p >0.05 we accept null hypothesis.
We cannot conclude that the mean shade of Mezza Perla tile (µ) is greater than 204.8