Answer:
-16
Step-by-step explanation:

Answer:
The value of x is 21.
Step-by-step explanation:
Since this is a right angle triangle, you can apply Pythagoras theorem, side² + side² = hypo² :
(x + 3)² + 10² = (x + 5)²
x² + 6x + 9 + 100 = x² + 10x + 25
x² + 6x + 109 - x² - 10x - 25 = 0
-4x + 84 = 0
-4x = -84
4x = 84
x = 84 ÷ 4
x = 21 units
Answer:
option C

Step-by-step explanation:
we have

using a graphing tool
see the attached figure N
The range is the interval--------> (-∞,8]

case A) 
using a graphing tool
The range is the interval--------> [-8,∞)

case B) 
using a graphing tool
The range is the interval--------> [8,∞)

case C) 
using a graphing tool
The range is the interval--------> (-∞,8]

case D) 
using a graphing tool
The range is the interval--------> (-∞,-8]

IT is c i checked using all the steps
The <em>echo</em> number 20222022202220222022 is the <em>perfect</em> square of 4496890281.
<h3>What echo number is a perfect square</h3>
An <em>echo</em> number has a <em>perfect</em> square if its square root is also a <em>natural</em> number. After some iterations we found that <em>echo</em> number 20222022202220222022 is a <em>perfect</em> square:

The <em>echo</em> number 20222022202220222022 is the <em>perfect</em> square of 4496890281. 
To learn more on natural numbers, we kindly invite to check this verified question: brainly.com/question/17429689