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3 years ago

5(2x - 8) + 15 = -15

1 answer:

7 0

First, you would follow PEMDAS, so the parenthasis are first. Since you can't subtract 2x and 8, you would distribute to 5. This would make the problem 10x-45+-15. They you would add 45, so that the problem would become 10x=30. Finally, you would divide the entire problem by 10 so that you isolate the variable x=3

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The sum of three decimal numbers is six exactly one of the numbers is less than one what could those numbers be

kompoz [17]

2+3.5+.5 could be a possible answer

4 0

3 years ago

Given the following group of numbers (8, 12, 4, 8, 6, 0, 9, 11, 3, 10) which of the following is (are) true? The mean is 7.1 The

agasfer [191]

Answer:

The mean is 7.1

The median IS NOT 1.6 (its 8)

The mode IS NOT 0 (its 8)

Step-by-step explanation:

3 0

4 years ago

Weekly wages at a certain factory are

Furkat [3]

Answer: 0.1359

Step-by-step explanation:

mean = $400

Standard deviation = $50

Since the wages is normally distributed , the first thing is to find the z - score.

z = $\frac{x-mean}{standard deviation}$

finding the z - value for 300 and 350 , we have

z = $\frac{300-400}{50}$

z = $\frac{-100}{50}$

2 = -2

also

z = $\frac{350-400}{50}$

z = $\frac{-50}{50}$

z = -1

The next thing is to check the calculated value on z - table.

From z - table :

P (z $\leq$ -2 ) = 0.0228

P ( z $\leq -1$ ) = 0.1587

combining the two

P ( -2 $\leq$ z $\leq$ -1 ) = 0.1587 - 0.0228

P ( -2 $\leq$ z $\leq$ -1 ) = 0.1359

Therefore , the the probability that a worker

selected at random makes between

$300 and $350 = 0.1359

3 0

3 years ago

Which polynomial is represented by the tiles ??

Reika [66]

$2 {x}^{2} - {x}^{2} = x {}^{2} \\ - 3x + 2x = - x \\ - 2 + 6 = 4 \\ so \: the \: answer \: would \: be \\ b. \: x {}^{2} - x +4$
Hope this helps

5 0

3 years ago

Read 2 more answers

A pilot flying at an altitude of 1.8km sights the runway directly in front of her. The angle of depression to the beginning of t

Dennis_Churaev [7]

Answer:

The answer is a

Step-by-step explanation:

The distance from the near end of the runway to the plane, divided by the altitude is the tangent of (90 degrees minus the angle of depression). Let "d1" be the distance to the near end of the runway, and "d2" be the distance to the far end of the runway. Let "a" be the altitude of the plane.

d1/a = tan(90 - 31)

d1 = a*tan(90 - 31)

d2/a = tan(90 - 23)

d2 = a*tan(90 - 23)

runway length = d2 - d1 = a*(tan(67) - tan(59))

length = 1800*(.6916) = 1245m = 1.2km

the answer is "a"

6 0

3 years ago

Read 2 more answers