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Paraphin [41]
3 years ago
5

What is the value of x when solving the equation Negative 2 x + (negative 8) = 2 x + 8 using algebra tiles?

Mathematics
2 answers:
mestny [16]3 years ago
7 0

Answer:

the first option ...-4

Step-by-step explanation:

ella [17]3 years ago
3 0

Answer:

The Answer is A.) -4

Step-by-step explanation:

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Got another question for you lovely folk, don’t understand how to do this one either
Brrunno [24]

Answer:

97.12°

Step-by-step explanation:

the value of the highlight angle =

tan~¹ 1/3 + tan~¹ 5/1 =

18.43° + 78.69° = 97.12°

7 0
2 years ago
To begin a bacteria study, a petri dish had 2800 bacteria cells. Each hour since, the number of cells has increased by 7.2%. Let
Rudiy27
The function that models exponential growth is:

P(t) = P0*(1 + r)^t, where

P0 = P(0) is the initial value of P

r is the growth rate as a decimal

In our case we have:

P(0) = 2800

r = 0.035 or 3.5%

P(t) = 2800*(1 + 0.035)^t

P(t) = 2800*(1.035)^t

The same exponential function written using y and t is:

y = 2800*1.035^t.

Explanation: https://softmath.com/algebra-word-problems/to-begin-a-bacteria-study-a-petri-dish-had-2800-bacteria
7 0
3 years ago
2x-9<-1 pleassssssse help me​
e-lub [12.9K]

Answer:

x <4

Step-by-step explanation:

2x-9<-1

Add 9 to each side

2x-9+9<-1+9

2x < 8

Divide each side by 2

2x/2 < 8/2

x <4

5 0
3 years ago
Evaluate (solve) the power: 2^9
german

Answer:

The corrext answer is, 512.

3 0
3 years ago
Read 2 more answers
A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
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