Answer:
97.12°
Step-by-step explanation:
the value of the highlight angle =
tan~¹ 1/3 + tan~¹ 5/1 =
18.43° + 78.69° = 97.12°
The function that models exponential growth is:
P(t) = P0*(1 + r)^t, where
P0 = P(0) is the initial value of P
r is the growth rate as a decimal
In our case we have:
P(0) = 2800
r = 0.035 or 3.5%
P(t) = 2800*(1 + 0.035)^t
P(t) = 2800*(1.035)^t
The same exponential function written using y and t is:
y = 2800*1.035^t.
Explanation: https://softmath.com/algebra-word-problems/to-begin-a-bacteria-study-a-petri-dish-had-2800-bacteria
Answer:
x <4
Step-by-step explanation:
2x-9<-1
Add 9 to each side
2x-9+9<-1+9
2x < 8
Divide each side by 2
2x/2 < 8/2
x <4
Answer:
The corrext answer is, 512.
Answer:
Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Step-by-step explanation:
We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.
So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;
Z =
~ N(0,1)
where,
= average age of the random sample of horses with colic = 12 yrs
= average age of all horses seen at the veterinary clinic = 10 yrs
= standard deviation of all horses coming to the veterinary clinic = 8 yrs
n = sample of horses = 60
So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(
12)
P(
12) = P(
) = P(Z
1.94) = 1 - P(Z < 1.94)
= 1 - 0.97381 = 0.0262
Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.