Solving the complex number, we get the value of the missing value that is ‘a’ = -6
We have been given the expression as
|a – i| = √37 (1)
Which is an expression of complex number. The general expression of complex number is given as
z = x + iy
where x is the real part and iy is the imaginary part
To find the modulus value, the formula is given by,
|z| = |x + iy|
|z| = √[(real part)2 + (imaginary part)2]
|z| = √(x2 + y2)
According to the question, |z| = √37 (2)
Equating equation (1) and (2), we get
√(a2 + 1) = √37
(a2 + 1) = 37
a2 = 37 – 1
a2 = 36
a = √36
a = ±6
Now value of a can be 6 or -6. We have been given that the modulus is in third quadrant.
Hence the value will be negative. Therefore, the missing value will be -6.
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Answer:
15c+12y
Step-by-step explanation:
6c + 7c + 5y + 2c + 7y
13c+2c +12y
15c+12y
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You are right to circle both 10 or 12. Neither can be solved without knowing something about the x values in 10 and the x value of the smaller base in 12.
Answer:
Diameter of a circle = 1.6 Cm
Step-by-step explanation:
Given:
Distance between first and third coins = 3.2 cm
Find:
Diameter of the coins = ?
Computation:
Number of circle = 3
In the given figure,distance between the first and third coins is 3.2 cm.
So,
Distance = 1st circle radius + 2nd circle diameter + 3rd circle radius
Distance = 1st circle radius + 2 (radius) + 3rd circle radius
Distance = R + 2R + R
3.2 Cm = 4 R
Radius = 0.8 Cm
Diameter of a circle = 2 × radius
Diameter of a circle = 2 × 0.8
Diameter of a circle = 1.6 Cm
It is g(x) =2 there I guessed hope correct.
