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3 years ago

What is the answer for 44/p= 11/5 p=_____

Mathematics

1 answer:

Alex73 [517]3 years ago

4 0

The answer to your question is p=20

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How many quarts are there in 10 ½ gallons

aksik [14]

Answer:

42 quarts

Step-by-step explanation:

7 0

3 years ago

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Some teenagers collected trash for a beach cleanup. The data for the number of pounds of trash collected by each teenager are sh

Mumz [18]

Answer:

4.66

Step-by-step explanation:

We are given the following data

26, 26, 21, 22, 20, 25, 35

Step 1

We find the Mean

Mean = 26+ 26+ 21+ 22+20+25+ 35/7

= 175/7

= 25

Step 2

We find the Standard Deviation

The formula for Standard deviation that we would use is the Population Standard deviation, this is because the data given above is the data of the number of pounds of trash collected by each teenager

= √(x - Mean)²/n

= √(26 - 25)²+( 26 - 25)²+ (21 - 25)²+ (22 - 25)² +(20 - 25)²+(25 - 25)²+ (35 - 25)²/7

= √152/7

= √21.7142857

= 4.65985898

Approximately = 4.66

5 0

3 years ago

Read 2 more answers

I travelled at 60km/h and took 2 hours for a certain journey. How long would it have taken me if I had travelled at 50km/h?

Marina86 [1]

Answer:

2 hours and 24 minutes

Step-by-step explanation:

2 hours at 60 km/h means you have travelled 2*60=120 km

120 km at 50 km/h takes 120/50 = 2.4 hours

2.4 hours is 2 hours and 0.4*60 = 24 minutes.

7 0

4 years ago

Please help me evaluate the expression 10a + 7 if a =1/5

sattari [20]

Answer:

Step-by-step explanation:

10a+7

<u>10(1/5)</u> + 7

6 0

3 years ago

A colony of bacteria is grown under ideal conditions in a laboratory so that the population increases exponentially with time. A

Naddik [55]

Answer:

Initial bacterias = 6006000

Altought I believe is safe to assume that the values were 192,000 and 384,000 instead of 192,192,000 and 384,384,000, in that case the initial bacterias is 6000

Step-by-step explanation:

A exponential growth follows this formula:

Bacterias = C*rⁿ

C the initial amount

r the growth rate

n the number of time intervals

Bacterias (55 hours) = 192,192,000

Bacterias (66 hours) = 384,384,000

$Bacterias(55hours)=C*r^{{\frac{55-t}{t}}} \\Bacterias (66hours) = C*r^{\frac{66-t}{t}}}$

If you divide both you can get the growth rate:

$\frac{Bacterias (66hours)}{Bacterias(55hours)}=\frac{C*r^{\frac{66-t}{t}}}{C*r^{{\frac{55-t}{t}}}} \\\frac{384,384,000}{192,192,000} =r^{\frac{66-t}{t} -\frac{55-t}{t} } \\2 =r^{\frac{11}{t}}$

So with that r = 2 and each time interval correspond to 11 years

Then replacing in one you can get the initial amount of C

$Bacterias (55hours)=C*2^{\frac{55-11}{11} } 192,192,000 = C*32\\C= 6006000$

7 0

3 years ago