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Yuki888 [10]
3 years ago
10

Change the fraction 4/13 to a decimal

Mathematics
2 answers:
erik [133]3 years ago
7 0
<em>4÷13</em>
<em>=0.307692</em>

<em>Good homework :)</em>
Maksim231197 [3]3 years ago
6 0
= 4/13

= 4 ÷ 13

= 0.307692
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Sheila bought some rose plants and sunflower plants.There were 35 rose plants than sunflower plants.If the ratio of the rose pla
DENIUS [597]
So assuming that youmeans there were 35 MORE rose plants than sunflower seeds, then

Rose:Sunflower =8:3

rose=sunflower+35
therefor

8 units=rose
3 units=sunflowers

rose-35=sunflower
8unit-35=3unit
5unit-35=0
5unit=35
therefor
35=5unit
divide by 5
7=1unit


so 8 units of roses

7 times 8=56

3 units of sunflowers
3 times 7=21

rose=56
sunflower=21
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3 years ago
SOMEONE PLEASE HELP ME ASAP
Alenkinab [10]
The answer to this question is C I just worked it out on paper using a calculator

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2 years ago
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What is the approximate volume of the cylinder? Use 3.14 for π.<br> 9 Hight and 4 length.
krek1111 [17]

Answer:

113.04

Step-by-step explanation:

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5 0
2 years ago
What is nearest $ 8.66 to nearest $
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What is the remainder of the quantity 5 x cubed plus 7 x plus 5 end quantity divided by the quantity x plus 2 end quantity? Show
jarptica [38.1K]

The remainder of the polynomial equation is -49

<h3>What is a remainder of a polynomial equation?</h3>

The remainder of a quantity in an algebraic expression of a polynomial equation is the remaining amount of the quantity left and can not be divisible by the divisor.

From the given information, we are to find the remainder of the given algebraic equation:

\mathbf{= \dfrac{5x^3+7x+5}{x+2} }

Using the long division method, we have:

\mathbf{= \dfrac{5x^3+7x+5}{x+2} } \implies \mathbf{5x^2 + \dfrac{-10x^2+7x+5}{x+2}}

Divide by \mathbf{ \dfrac{-10x^2+7x+5}{x+2}}, we have:

\mathbf{= 5x^2- 10x+ \dfrac{27x+5}{x+2}}

Divide by \mathbf{\dfrac{27x+5}{x+2}}, we have:

\mathbf{= 5x^2- 10x+ 27 +\dfrac{-49}{x+2}}

Learn more about finding the remainder of a polynomial equation here:

brainly.com/question/24978997

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