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ddd [48]
2 years ago
15

triangle has sides measuring 2 inches and 7 inches If x represents the length in inches of the third side which inequality gives

the range of possible values for x?
Mathematics
1 answer:
il63 [147K]2 years ago
6 0
We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (<span>Triangle Inequality Theorem)
so
inequality 1
</span>(2+7) \ \textgreater \  x \\  9 \ \textgreater \  x \\  x \ \textless \  9 in
<span>
inequality 2
</span>(x+2) \ \textgreater \  7 \\  x \ \textgreater \  7-2 \\  x \ \textgreater \  5 in
<span>
the answer is
</span>5 in  \ \textless \ x \ \textless \ 9 in<span>
</span>
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17 dollars total for Jose and Mila's jelly beans.

<em>Add 1.5 and 2.75 together to get 4.25</em>

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2 years ago
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3 years ago
Fifty-eight boys were asked if they play football and/or baseball. Thirty-one of them said they do not play baseball. Sixteen of
Arte-miy333 [17]
The two-way table is attached.

We start out placing 31 in the Total column beside the Don't Play Baseball row.  We then place 16 in the Total row under the Play Football column.  20 goes in the Don't Play Baseball row under the Don't Play Football column.

Since there are 31 people that do not play baseball, and 20 of them don't play football, this leaves us with 31-20=11 that do not play baseball and play football.

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4 0
3 years ago
Find the volume of a right circular cone that has a height of 14.3 ft and a base with a diameter of 17.2 ft. Round your answer t
saveliy_v [14]

Answer:

Volume of the given cone is 1107.6 cubic feet.

Step-by-step explanation:

Formula to get the volume of a right circular cone is,

V = \frac{1}{3}\pi r^{2}h

Here r = radius of the circular base

h = height of the cone

Now we put the values in the given formula

Volume = \frac{1}{3}\pi (8.6)^2(14.3)  [ radius = \frac{17.2}{2}=8.6 ]

             = \frac{1057.628\pi }{3}

             = 1107.55

             ≈ 1107.6 cubic feet

Therefore, volume of the given cone is 1107.6 cubic feet.

6 0
2 years ago
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4 0
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