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n200080 [17]
2 years ago
9

How did you determine ray​

Mathematics
2 answers:
amid [387]2 years ago
6 0

Answer:

A ray is a part of a line that has one endpoint and goes on infinitely in only one direction. You cannot measure the length of a ray. A ray is named using its endpoint first, and then any other point on the ray (for example, →BA ).

Effectus [21]2 years ago
3 0

Answer:

In naming a ray, we always begin with the letter of the endpoint (where the ray starts) followed by another point on the ray in the direction it travels. Since the vertex of the angle is the endpoint of each ray and our vertex is , each of our rays must begin with . Only fails to do so.

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Which equation can be used to solve for the unknown number? Seven less than a number is thirteen.
zysi [14]

Answer:

n-7=13

Step-by-step explanation:

We need to find an equation that represents the expression: "Seven less than a number is thirteen".

It means that a number minus 7 equals 13. So, the correct option is: n-7=13

Bonus: Solving for 'n' we have that n=20.

So, Seven less than 20 equals 13!!

7 0
3 years ago
Read 2 more answers
Lines P and Q are parallel. What is the measure of angle 1
oksian1 [2.3K]

Answer:

Next time show a picture

Step-by-step explanation:

But! A way you could solve this is to look at the opposite angle of 1 and see what the number is. The number opposite of 1 is always equal to 1. You could also see if there is a number next to 1. The number next to 1 +1= 180 degrees. Good luck!

8 0
3 years ago
Identify which line from the graph the following right triangles could lie on.
qaws [65]

Answer:

Step-by-step explanation:

Slope of line A = \frac{\text{Rise}}{\text{Run}}

                         = \frac{9}{3}

                         = 3

Slope of line B = \frac{9}{6}

                         = \frac{3}{2}

Slope of line C = \frac{6}{8}

                         = \frac{3}{4}

5). Slope of the hypotenuse of the right triangle = \frac{\text{Rise}}{\text{Run}}

                                                                                = \frac{90}{120}

                                                                                = \frac{3}{4}

Since slopes of line C and the hypotenuse are same, right triangle may lie on line C.

6). Slope of the hypotenuse = \frac{30}{10}

                                              = 3

Therefore, this triangle may lie on the line A.

7). Slope of hypotenuse = \frac{18}{24}

                                        = \frac{3}{4}

Given triangle may lie on the line C.

8). Slope of hypotenuse = \frac{21}{14}

                                        = \frac{3}{2}

Given triangle may lie on the line B.

9). Slope of hypotenuse = \frac{36}{24}

                                        = \frac{3}{2}

Given triangle may lie on the line B.

10). Slope of hypotenuse = \frac{48}{16}

                                          = 3

Given triangle may lie on the line A.

7 0
3 years ago
Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.
Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

<u>Step 1</u>

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

<u>Step 2</u>

Using the distance formula

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Given E(-2,3), F(1,6)

|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}

Given F(1,6), G(4,3)

|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}

Given G(4,3), H(1,0)

|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}

Given E (−2, 3), H (1, 0)

|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}

<u>Step 3</u>

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|=\frac{6-3}{1+2} =\frac{3}{3}=1

Segment GH, G (4, 3), H (1, 0)

Slope of |GH|= \frac{0-3}{1-4} =\frac{-3}{-3}=1

<u>Step 4</u>

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH|= \frac{0-3}{1+2} =\frac{-3}{3}=-1

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| =\frac{3-6}{4-1} =\frac{-3}{3}=-1

<u>Step 5</u>

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

<u>Step 6</u>

<u>Segment EF, segment FG, segment GH, and segment EH are congruent. </u>

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

<u>Step 7</u>

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0
3 years ago
Read 2 more answers
Can someone help me with this
11Alexandr11 [23.1K]

-6 + x = -7

+6        +6        add 6 to both sides, 6's cancel out on the left.

________

x = -1, is the answer.

Hope this helps! Let me know if you have any other questions related to this problem. :)

5 0
2 years ago
Read 2 more answers
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