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Fynjy0 [20]
4 years ago
12

Solve the following system of equations algebraically for all values of x,y and z

Mathematics
1 answer:
Rudiy274 years ago
6 0
X + 3y + 5z = 45
6x - 3y + 2z = - 10
------------------------add
7x + 7z = 35

6x - 3y + 2z = -10
-2x + 3y + 8z = 72
----------------------add
4x + 10z = 62

7x + 7z = 35....multiply by 4
4x + 10z = 62...multiply by -7
---------------------
28x + 28z = 140 (result of multiplying by 4)
-28x - 70z = - 434 (result of multiplying by -7)
--------------------add
- 42z = - 294
z = -294/-42
z = 7

4x + 10z = 62
4x + 10(7) = 62
4x + 70 = 62
4x = 62 - 70
4x = - 8
x = -8/4
x = -2

x + 3y + 5z = 45
-2 + 3y + 5(7) = 45
-2 + 3y + 35 = 45
3y + 33 = 45
3y = 45 - 33
3y = 12
y = 12/3
y = 4

solution is (-2,4,7) <==
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