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zheka24 [161]
3 years ago
6

Find the area of a parallelogram with height 4 4/5 and base is 5 2/3

Mathematics
2 answers:
AlexFokin [52]3 years ago
6 0
This parallelogram has an area of 27.17.

To find this you use the formula a = bh

So when you fill in base (b) and height (h) with the values provides you get the formula a = 5.66 x 4.8 then you just multiply those two numbers together. If you don't understand any part of this, please let me know and I will explain in more detail.
wel3 years ago
3 0
A = bh

b=5\dfrac{2}{3}=\dfrac{5\cdot3+2}{3}=\dfrac{17}{3}\\\\h=4\dfrac{4}{5}=\dfrac{4\cdot5+4}{5}=\dfrac{24}{5}\\\\A=\dfrac{17}{3}\cdot\dfrac{24}{5}=\dfrac{17}{1}\cdot\dfrac{8}{5}=\dfrac{17\cdot8}{1\cdot5}=\dfrac{136}{5}=27.2

Answer: A = 27.2.
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H (4, -8) is the pre-image. What is the new prime image after a dilation with a scale factor of 1/2?
Marina CMI [18]

Answer:

(2, -4)

Step-by-step explanation:

The scale factor is the number used to multiply the pre-image coordinates.

The image of the point (4, -8) is (2, -4).  Each coordinate is 1/2 the corresponding coordinate in the pre-image.

8 0
3 years ago
Heeeeeelpppppppppp<br> Meeeeeeeee<br><br> Find the missing lengths.
erica [24]

Answer: thw 2 one is the answer

Step-by-step explanation:

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B4%7D%20%20-%206%20%7Bx%7D%5E%7B3%7D%20%20%2B%2022%20%7Bx%7D%5E%7B2%7D%20%20-%2
alexira [117]

Answer:

x = 2, 1 + 3i, 1 − 3i

Step-by-step explanation:

Find the Roots (Zeros)

x^4 − 6x^3 + 22x^2 − 48x + 40

Set x^4 − 6x^3 + 22x^2 − 48x + 40 equal to 0. x^4 − 6x^3 + 22x^2 − 48x + 40 = 0

Solve for x.

Factor the left side of the equation.

Factor x^4 − 6x^3 + 22x^2 − 48x + 40 using the rational roots test.

(x − 2) (x^3 − 4x^2 + 14x − 20) = 0

 Factor x^3 − 4x^2 + 14x − 20 using the rational roots test.

(x − 2) (x − 2) (x2 − 2x + 10) = 0

 Combine like factors.

(x − 2)2 (x^2 − 2x + 10) = 0

If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

(x − 2)^2 = 0

x^2 − 2x + 10 = 0

 Set (x − 2)^2 equal to 0 and solve for x.

Set (x − 2)^2 equal to 0.

 (x − 2)^2 = 0

Solve (x − 2)^2 = 0 for x.

x = 2

 Set x^2 − 2x + 10 equal to 0 and solve for x.

Set x^2 − 2x + 10 equal to 0. x^2 − 2x + 10 = 0

Solve x^2 − 2x + 10 = 0 for x.

Use the quadratic formula to find the solutions.

−b ± (√b^2 − 4 (ac) )/2a

Substitute the values a = 1, b = −2, and c = 10 into the quadratic formula and solve for x.

2 ± (√(−2)^2 − 4 ⋅ (1 ⋅ 10))/2 ⋅ 1

Simplify.

Simplify the numerator.

  x =    2 ± 6i/ 2.1

Multiply 2 by 1

 x =  2 ± 6i/2⋅1

 Simplify

  2 ± 6i/2  

   x = 1 ± 3i

The final answer is the combination of both solutions.

x = 1 + 3i, 1 − 3i

The final solution is all the values that make (x − 2)2 (x2 − 2x + 10) = 0 true.

x = 2, 1 + 3i, 1 − 3i

3 0
3 years ago
What is the absolute davatation round to the nearest tenth for 6.3, 6.4, 6.5, 6.6, 6.8. 6.8, 7.5?
WITCHER [35]
Let's find the mean of all the values first.
6.3+6.4+6.5+6.6+6.8+6.8+7.5= 46.9
Let's divide by the number of values.
46.9÷7=
6.7
Now let's find the distance that each number is away from 6.7 and find the mean of those numbers.
0.4+0.3+0.2+0.1+0.1+0.1+0.8=
.2857
≈ 0.3
So, the absolute deviation is 0.3.
8 0
3 years ago
Read 2 more answers
How you will find out the value of 'n ' ?
saw5 [17]

Answer:

I don't know

Step-by-step explanation:

How you will find out the value of 'n ' ?

[ n! × 2^( n-4 ) / { 4! × ( n-4 )! } ] = [ n! × 2^( n-5 ) / { 5! × ( n-5 )! } ]

8 0
3 years ago
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