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Nata [24]
3 years ago
14

Does anyone happen to know these. Brainiest answer and highest points(23)

Mathematics
1 answer:
LenaWriter [7]3 years ago
4 0
1. 67 yards and 1 foot 
2. 3lbs 
3. 8 in. 1/4 
4. 860000 milligrams
5. 4.565 liters
6. 435 kilograms
7. 800 ounces
8. 6000 milliliters

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Area = length x width
kramer

Answer: It will cost him $237 to seed the entire backyard

Step-by-step explanation:

Hi, to answer this question, first, we have to calculate the area of the rectangular backyard:

Area of a rectangle = length x width

Replacing with the values given:

A = 20 x 15 = 300 ft2

Since seed cost 0.79 per square foot, we simply have to multiply that price by the area:

0.79 x 300 = $237

It will cost him $237 to seed the entire backyard

Feel free to ask for more if needed or if you did not understand something.

3 0
3 years ago
What is the diameter of a cone with height 8 m and volume 150 m3 ? (1 point 7.5 m 15 m?
Hitman42 [59]
This is the concept of volume of solid materials, we are required to find the diameter of cone with height 8 and volume 150 m^3.
volume of cone is given by;V=1/3 (pi*r^2*h)
making r^2 the subject we get;
V/(pi*h)=r^2
inserting the values in our formula we get:
150/(pi*8)=r^2
r^2=5.97
thus;
r=sqrt(5.97)=2.44
But ;
diameter=2*radius
thus
diameter=2.44*2
=4.88 m
3 0
3 years ago
Examine the summary section of the monthly credit card statement below. Use the first five entries to determine whether the new
rjkz [21]
Yea I’m gonna go watch my internet and then go to go home to go to
4 0
2 years ago
I NEED HELP!!!!! PLEASE ​
lys-0071 [83]

Answer:

I don't know

Step-by-step explanation:

your image is blocked on my computer. sorry

7 0
3 years ago
How do i solve this
tensa zangetsu [6.8K]
5.\\5^\frac{1}{4}\cdot5^\frac{1}{4}\cdot5^\frac{1}{4}=5^{\frac{1}{4}+\frac{1}{4}+\frac{1}{4}}=5^\frac{3}{4}=\sqrt[4]{5^3}=\sqrt[4]{125}\\\\/\text{used:}\ a^n\cdot a^m=a^{n+m}/\\6.\\\left(5^\frac{1}{4}\right)^6=5^{\frac{1}{4}\cdot6}=5^{\frac{1}{2}\cdot3}=5^\frac{3}{2}=5^{1\frac{1}{2}}=5\sqrt5\\\\/\text{used:}\ (a^n)^m=a^{n\cdot m}/
7.\\5^{-\frac{1}{4}}=\dfrac{1}{5^\frac{1}{4}}=\dfrac{1}{\sqrt[4]5}\\\\/\text{used:}\ a^{-n}=\dfrac{1}{a^n}/\\8.\\5^2\cdot5^\frac{1}{4}=5^{2+\frac{1}{4}}=5^{2\frac{1}{4}}=5^\frac{9}{4}=5^2\sqrt[4]5=25\sqrt[4]5

a^\frac{m}{n}=\sqrt[n]{a^m}
3 0
3 years ago
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