surface area of prisms. please help with the work shown because i can't figure out how to solve these :(
1 answer:
here: :)
I did the work, and basically i solved for the area of the faces and then multiplied that by two to get the total surface area of the faces. Then I added in the areas of the sides connecting the two faces:
just as a referral: the formulas to find the faces are as follows:
rectangle: length times width
circle: pi x r^2
trapezoid: h(base1 + base2)
and triangle: (b x h)/2
You might be interested in
I am not quite sure what the question asks for,
But this is what i assume it wants:
Cos A= 0.6489
In this given one, we basically find the size of the angle A
we do cosine inverse on both sides to get the size of the angle A
: It looks like this in the calculator
× cos A=(0.6489)
( and cos cancels out)
A=(0.6489)
A=49.54°
check:
cos 49.54=0.6489 (its right!)
But this is what i assume it wants:
Cos A= 0.6489
In this given one, we basically find the size of the angle A
we do cosine inverse on both sides to get the size of the angle A
(
A=
A=49.54°
check:
cos 49.54=0.6489 (its right!)