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iogann1982 [59]
3 years ago
11

Page 26 1.4 puzzle time did you hear about..​

Mathematics
2 answers:
Firlakuza [10]3 years ago
8 0

Answer:

No I didn't But thank you for asking

antoniya [11.8K]3 years ago
3 0
No never heard about it
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How many times does 33 go into 112?
Vadim26 [7]

Answer:

3.3939

rounded off = 3

33 goes in 112 3 times

6 0
3 years ago
Answer the question above on the ixl tab, please.
kramer

Answer:

<h2>The answer is 10</h2>

Step-by-step explanation:

The formula for finding the combination of two given positive numbers is given by

<h3>_{n}C _{r} =  \frac{n!}{(n - r)!r!}</h3>

Where n and r are positive numbers

From the question we have

5 C 3

<u>Simplify</u>

That's

<h3>\binom{5}{3}  =  \frac{5!}{(5 - 3)!3!}  =  \frac{120}{2! \times 3  !}  \\  =  \frac{120}{2 \times 6}  \\  =  \frac{120}{12}</h3>

We have the final answer as

<h3>10</h3>

Hope this helps you

8 0
3 years ago
5. Which of the following is not shown in the
soldi70 [24.7K]
C.
(I’m pretty sure but if I’m wrong I apologize in advance)
8 0
3 years ago
Total power generated by wind worldwide doubles every 3 years. In a particular year, the world wind-generating capacity was abou
IceJOKER [234]
<span>You are given the sum of the power created by wind worldwide which doubles every 3 years. In one an unknown year, the world wind generating capacity was about 91 thousand megawatts. You are asked for the growth rate. the growth rate formula is given below:

growth rate = (present / past)^(1/n)
2 = (present/91MW)^(1/3)
the present power is 728MW</span>
7 0
3 years ago
A B R and P are four points on a circle with centre 0. A O R and C are four points on a different circle. The two circles inters
Slav-nsk [51]

Answer:

x° = ∠OBR = ∠ABC (base angles of a cyclic isosceles trapezoid)

Step-by-step explanation:

APRB form a cyclic trapezoid

∠APO  = x° (Base angle of an isosceles triangle)

∠OPR  = ∠ORP (Base angle of an isosceles triangle)

∠ORB = ∠OBR (Base angle of an isosceles triangle)

∠APO + ∠OPR + ∠OBR = 180° (Sum of opposite angles in a cyclic quadrilateral)

Similarly;

∠ORB + ∠ORP + x°  = 180°

Since ∠APO = x° ∠ORB = ∠OBR and ∠OPR  = ∠ORP we put

We also have;

∠OPR = ∠AOP = ∠BOR (Alternate interior angles of parallel lines)

Hence 2·x° + ∠AOP = 180° (Sum of angles in a triangle) = 2·∠OBR + ∠BOR

Therefore, 2·x° = 2·∠OBR, x° = ∠OBR = ∠ABC.

6 0
3 years ago
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