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liraira [26]
3 years ago
9

Please can someone help me?

Mathematics
1 answer:
Feliz [49]3 years ago
7 0

Answer:

weight of a water=0.5

spherical ball is filled With water=0.95.

so dear for

22\7*0.5*0.95=1.49

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Please help whit all of them I can’t fail math it’s the only subject I’m failing in my mama would whoop me please
scoray [572]

I dunno I rlly don't know like seriously I'm in 7th

6 0
3 years ago
The following scores were obtained by 11 footballers in a goal-competition 536878311632. The median score was?
sineoko [7]

Answer:

3

Step-by-step:

1,1,2.2.3.3.3.5.6.6.7.8.8

more 3s than other numbers

median is 3

4 0
3 years ago
Can someone plzzz help with this ill give a pizza :((
nydimaria [60]

22 \times 18 = (20 + 2)(20 - 2) =  {20}^{2}  -  {2}^{2}  = 396

7 0
3 years ago
1. Si μ es un ángulo agudo y cot μ = , ¿cuáles son los valores de todas las funciones trigonométricas de μ?
Scilla [17]

Answer:

Funciones trigonométricas de μ

sen (μ) = b/ √(a^2+ b^2)

cos (μ) = a/ √(a^2+ b^2)

tan (μ)  = b/ a

cot (μ)  = a/ b

sec (μ) =  √(a^2+ b^2) / a

csc (μ) =   √(a^2+ b^2) /b

Step-by-step explanation:

Ya que no proportionaste el valor de cot μ podemos suponer un valor = a/b para que tengas una respuesta general y reemplaces el valor de a y b de acuerdo con tu caso.

cot (μ) = a/b

_______________________________

Funciones trigonométricas

sen (μ) = cateto opuesto/ hipotenusa

cos (μ) = cateto adyacente/ hipotenusa

tan (μ)  = cateto opuesto/ cateto adyacente

cot (μ)  = cateto adyacente/ cateto opuesto

sec (μ) =  hipotenusa / cateto adyacente

csc (μ) =   hipotenusa /cateto opuesto

cot (μ)  = cateto adyacente/ cateto opuesto = cot (μ)  = a/ b

Por lo tanto:

Cateto adyacente = a

Cateto opuesto = b

Hipotenusa

H^2 = Cateto adyacente^2 + Cateto opuesto^2

H= √(a^2+ b^2)

Reemplaznado los valores de los catetos y la hipotenusa se obteienen los valores de las funciones trigonométricas de μ.

8 0
3 years ago
feathered serpent pryimid is located in teotihuacan mexico. its base is a square that measures 65 m on each side the pyramid is
Oksanka [162]
The volume of a pyramid is the area of the base times the height all over 3. Then the answer is:

(65 * 65 * 19.4)/3

81965/3 is approximately:

27321.6666666667

Hope that helped 
8 0
4 years ago
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