Question

Item 1 A bag contains 7 blue cards, 4 green cards, 6 red cards, and 8 yellow cards. You randomly choose a card. a. How many possible outcomes are there?

Answer 1

Answer:

4 possible outcomes

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

so

$P=\frac{x}{y}$  

In this problem

The probability of choose a blue card is

$x=7$

$y=7+4+6+8=25$

substitute

$P=\frac{7}{25}$

The probability of choose a green card is

$x=4$

$y=7+4+6+8=25$

substitute

$P=\frac{4}{25}$

The probability of choose a red card is

$x=6$

$y=7+4+6+8=25$

substitute

$P=\frac{6}{25}$

The probability of choose a yellow card is

$x=8$

$y=7+4+6+8=25$

substitute

$P=\frac{8}{25}$

The sum of the probabilities of the 4 possible outcomes  is equal to

$\frac{7}{25}+\frac{4}{25}+\frac{6}{25}+\frac{8}{25}=\frac{25}{25}$ ----> represent the 100%