Answer:
there is no greatest load
Step-by-step explanation:
Let x and y represent the load capacities of my truck and my neighbor's truck, respectively. We are given two relations:
x ≥ y +600 . . . . . my truck can carry at least 600 pounds more
x ≤ (1/3)(4y) . . . . . my truck carries no more than all 4 of hers
Combining these two inequalities, we have ...
4/3y ≥ x ≥ y +600
1/3y ≥ 600 . . . . . . . subtract y
y ≥ 1800 . . . . . . . . multiply by 3
My truck's capacity is greater than 1800 +600 = 2400 pounds. This is a lower limit. The question asks for an <em>upper limit</em>. The given conditions do not place any upper limit on truck capacity.
1. -.6 or -3/5
2. -.4 or -4/9
2x + 3y = 1,470
To solve using the slope intercept method, we need to solve for y.
First, subtract 2x from each side.
3y = -2x +1470
The, we need to divide both sides of the equation by by 3 to solve for y
y = -2/3 x + 490.
We know the y intercept is 470, which means on the y axis we place at point at positive 490. The slope is -2/3. We go down 2 units and over to the right 3 units and place a point. We draw a line connecting these two points extending only to the right until it reaches the x axis. We cannot have negative x because we cannot sell negative lunch specials. We cannot have negative y, because y is the number of specials sold.
Answer:
A. 5 + 2.75 · S ≤ 21
Step-by-step explanation:
So we know that it has to be less than or equal to $21 because that's all she has to spend. So we can automatically rule out the equations with ≥ because that means greater than.
We can also rule out the equations that have 50 at the very end because that's just how far she wants to travel.
