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2 years ago

0.4444444 into a fraction

1 answer:

5 0

Step 1: Write down the decimal divided by 1.
Step 2: Multiply both top and bottom by 10 for every number after the decimal point. (For example, if there are two numbers after the decimal, then use 100, if there are three then use 1000, etc.) 

answer is 
4/9

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. Mariam picks 9 2/20 kilograms of oranges. She gives 2 1/4 kilograms to her mother.

otez555 [7]

Answer:

a) 6 17/20

b) 10 31/60

Step-by-step explanation:

a) 9 2/20 - 2 1/4 = 137/20 = 6 17/20

b) 6 17/20 + 3 2/3 = 631/60 = 10 31/60

5 0

2 years ago

Given f(x)=5-3x, if f(x)=-19, find x

Dafna1 [17]

X would equal 8

Step-by-step explanation:

5-3(8) = -19

5 multiplied by negative 3 times 8 equals negative 19

negative 3 times 8 equals negative 24 plus 5 equals 19

7 0

3 years ago

Which ordered pairs make both inequalities true?

Arlecino [84]

Answer:

(0,-2) and (1, 1)

Step-by-step explanation:

7 0

3 years ago

Complete the following invoice for upholstery fabric.

Degger [83]

Answer:

a) $49.48

b) $220921.91

Step-by-step explanation:

(a) 4 yd @ $12.37 per yd = 4 x $12.37 = $49.48

(b) 271 yd @ 815.21 per yd = 271 x $815.21 = $220921.91

(c) 20% yd @ $4.95 per yd : Here the nunber of yards are missing. Hence could not be answer . However if number of yards is x . The answer would be

20% of 4.95x

(20%=0.20)

0.20 × 4.95x

8 0

3 years ago

What is the asymptote for the graph of this logarithmic function? f(x) = log3(x – 1)

Pepsi [2]

Answer:

Vertical Asymptote:

$x=1$

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

$f(x)=log_3(x-1)$

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

$x-1=0$

we get

$x=1$

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}log_3(x-1)$

$\lim_{x \to \infty} f(x)=log_3(\infty-1)$

$\lim_{x \to \infty} f(x)=undefined$

so, it does not exist

7 0

3 years ago

Read 2 more answers