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2 years ago

A right triangle has a height of 27 inches and a base of 30 inches what is the area of the triangle

Mathematics

1 answer:

klasskru [66]2 years ago

7 0

Answer:

The answer is 405

Step-by-step explanation:

FIrst you would do 27 times 30 which is 810 then you would divided by 2 which in turn gives you 405

Hope this helped!

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kali has a 6 centimeter ladder and puts the base of the ladder 2 meters away from the tree how high into the tree will the lader

weqwewe [10]

I am going to assume ‘centimetre’ was a typo.

A^2 + B^2 = C^2

C^2 - A^2 = B^2

32 = B^2

Square root both sides

B = 5.7m high

The ladder will reach 5.7 meters high

5 0

3 years ago

A game show awards 30 points for each correct answer and deducts 50 points for each in correct answer. A contestant answers 2 qu

mina [271]

Answer:

-10 points

Step-by-step explanation:

A game show awards 30 points for each correct answer and deducts 50 points for each in correct answer. A contestant answers 2 questions incorrectly and 3 questions correctly. What is his final score?

Let us say Initial number of points = 0

Hence,

He answers 2 incorrectly = 0 - 50 - 50

= -100

He answers 3 correctly =-100 + 30 + 30 + 30

His final score = -100 + 30 + 30 + 30

= -10 points

8 0

2 years ago

Solve 2x^2 + x - 4 = 0 <br> X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0

3 years ago

Someone Help me solve these by substitution please !

PSYCHO15rus [73]

I think the answer is:

X=3

Y=-2

8 0

2 years ago

I need help with identifying parallel and perpendicular lines from equations.

Semenov [28]

For the first one, lines one and two are perpendicular because they have opposite slopes. Parallel lines share the same slope

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2 years ago