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FinnZ [79.3K]
3 years ago
5

Each year ,a school sends 50 students to a conference . last year , the cost was $12.50 per student.this year ,the cost per stud

ent has increased by 16%.what is the total cost to 50 students to the conference this year?answer
Mathematics
1 answer:
Sladkaya [172]3 years ago
3 0
Well first you figure out how much more it is to pay for one student. You multiply 12.50 by 1.15 to find that out. This gives you 14.50, which is the price for one student.
To find out the price for 50, just multiply by 50, which is $725.
Answer: $725
Conclusion: This school is ripping people off.
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MATH HELP!!!
AfilCa [17]
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multiply that by number of years until he retires:

761280 / 29280 = 26 years

292800 / 29280 = 10 years

the other 2 arent even years so it should be one of those 2. I would say the larger number




4 0
3 years ago
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Romashka [77]

Answer:

u=95

Step-by-step explanation:

To solve this problem we need to isolate 'u' variable using properties of equation.

Lets multiply by -9 the whole equation

u - -23=-8*9

Remember keys features of algebra:

- * - = +

- * += -

+ * - = -

+ * + =+

So, our equations becomes>

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8 0
3 years ago
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Can someone helpp pleaseee, ill paypal you 15$
svetoff [14.1K]

Step-by-step explanation:

The angles on the same side of the parallel lines and the transversal are called corresponding angles.

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So both are 100 degrees

7 0
2 years ago
Do male and female servers work the same number of hours? A sample of 25 female servers worked an average of 26 hours per week,
Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

Given that

Group   Group One     Group Two  

Mean       26.00 23.00

SD                 2.00 4.00

SEM         0.40 1.21

N                     25     11    

where group I represents female servers and group II male servers.

We have to calculate confidence interval for 90% for difference in means

The mean of Group One minus Group Two equals 3.00

df = 34  

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t critical = 2.034 for 90% df 34

Hence confid. interval at 90%

=Mean diff ±2.034 * std error of diff

= (0.98, 5.02)

5 0
3 years ago
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