Can someone please help me?
1 answer:
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Step-by-step explanation:
here is the answer babe. Feel free to ask for more help
Answer:
Step-by-step explanation:
From the picture attached,
Area of ΔECD =
=
From ΔEFD,
sin(32°) =
sin(32°) =
EF = 14 × sin(32°)
= 7.42 cm
By cosine rule,
EC² = DE² + CD² - 2(DE)(CD)cos(32°)
EC² = 14² + 27² - 2(14)(27)cos(32°)
EC² = 196 + 729 - 641.12
EC² = 283.88
EC = 16.85 cm
Area of ΔECD = Area of ΔAEB =
= 100.17
Area of ΔECD + Area of ΔAEB = 2(100.17)
= 200.34 cm²
Area of sector BEC =
Here, θ = central angle of the sector
Area of sector BEC =
=
= 260.16 cm²
Area of the logo = Area of triangles AEB + Area of triangle ECD + Area of sector BEC
= 200.34 + 260.16
= 460.50
≈ 460 cm²
