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djverab [1.8K]
3 years ago
8

cassidy loves black and yellow jelly beans she noticed when she was counting them that she had 7 less than three times as many b

lack jelly beans as she had yellot jelly beans in total she counted 225 jelly beans how many black jelly beans did she have?
Mathematics
1 answer:
Dmitriy789 [7]3 years ago
4 0
Most of the information's are already given in the question. It is important to understand the language of the problem for solving the problem. Once the language is understood, then solving the problem is easy.
Let us assume the number of black jelly beans = x
Number of yellow jelly beans = y
Then from the question we can get to a equation.
3x - 7 = y
We also know from the question that
x + y = 225
x + 3x -7 = 225
4x = 225 + 7
4x = 232
x = 232/4
   = 58
So Cassidy has 58 black jelly beans out of the total of 225 jelly beans
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Step-by-step explanation:

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A basketball team played six games. In those games, the team won by 7 points, lost by 7, won by 8, won by 9, lost by 4, and won
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Based on the difference in scores for the basketball team over the six games, the mean difference in scores was 3

<h3>How to find the mean difference in scores?</h3>

The basketball team had 6 games and in these games, their scores were listed as differences in game scores.

The mean of these differences in scores can be found by adding the differences where they won and subtracting the differences where they lost and then dividing by the number of games:

The mean difference in game scores is:

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The total resistance in a circuit with two parallel resistors is 2 ohms and R1 is 6 ohms. Using the equation for R2, in terms of
ivanzaharov [21]
<h2>Answer:</h2>

R_2  is 3 ohms

<h2>Step-by-step explanation:</h2>

In a circuit containing two resistors R_1 and R_2 connected together in parallel, the total resistance R_T is given by;

\frac{1}{R_T} = \frac{1}{R_1}  + \frac{1}{R_2}              ---------(i)

<em>Make </em>R_2<em> subject of the formula;</em>

=> \frac{1}{R_2} = \frac{1}{R_T}  - \frac{1}{R_1}  

=> \frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}

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From the question,

R_1 = 6Ω

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