Answer:
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Answer: 
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
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Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following:

Hmmm I think either D or C
Answer:
We can start by figuring out how much he traveled per gallon. To do so all we need to do is divide the amount of miles he drove by the gallons it took him to drive that distance (348/12). This comes out to 29 miles. THerefore he drives 29 miles per gallon of gasoline.
Now to find how far he traveled with 8 gallons we need to multiply 29 times 8 (miles per gallon times how many gallons he used)
Your answer is 232
Step-by-step explanation: