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Ad libitum [116K]

3 years ago

11

Please help me I am at school and I need the answer now

1 answer:

Lerok [7]3 years ago

4 0

I will try my best are there answers

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A shipment of 12 microwave ovens contains three defective units. A vending company has ordered four units, and because each has

statuscvo [17]

Answer:a) 54/55

b) 100/110

c) 99/110

Step-by-step explanation:

a)Probability of ordering 4= 9/12×3/11×2/10×1/9 = 54/11880

Probability of 4 good units= 4 × 54/11880

= 216/11880

1/55

1-(1/55) = 54/55

b)Probability of 2 good units= 2 × 54/(11880)

= 108/11880

= 1/110

1- (1/110)= 100/110

c) Probability of exactly 2 units not good= 1 -(100/110) =99/110

8 0

3 years ago

If ABC=85,CBD=140 , and ,ABD=1/2x=30 find the value of x.

nexus9112 [7]

Based on the given nomenclature of angles, I think the illustration would look like that shown in the attached picture. The common vertex is point B, that's why the middle point of the given angles is B. Now, according to Angle Addition Postulate, the individual interior angles should sum up to the total angle. So, the equation would be

m∠ABD = m∠ABC + m∠CBD
m∠ABC = m∠ABD - m∠CBD
m∠ABC = 85° - m∠CBD

Read more on Brainly.com - brainly.com/question/5023714#readmore

5 0

4 years ago

Read 2 more answers

Based on historical data in Oxnard college, we believe that 37% of freshmen do not visit their counselors regularly. For this ye

slega [8]

Answer:

A sample size of 1031 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

37% of freshmen do not visit their counselors regularly.

This means that $\pi = 0.37$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?

A sample size of n is required.

n is found when M = 0.035. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.035 = 2.327\sqrt{\frac{0.37*0.63}{n}}$

$0.035\sqrt{n} = 2.327\sqrt{0.37*0.63}$

$\sqrt{n} = \frac{2.327\sqrt{0.37*0.63}}{0.035}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.37*0.63}}{0.035})^2$

$n = 1030.4$

Rounding up:

A sample size of 1031 is required.

4 0

3 years ago

A store sold 70 copies of a magazine for $350. Each copy of the magazine costs the same. Which equation and set of ordered pairs

Ainat [17]

The answer is C. 5x

We need to find the price of one magazine. To do this we divide 350 by 70

350 / 70 = $5 per magazine

8 0

3 years ago

Read 2 more answers

A company produces x units of a product per month, where c(x) represents the total cost and r(x) represents the total revenue fo

Nat2105 [25]

Answer:

The total profit P(x) or the month is $P(x)=-0.5x^2+500x-350$ .

Step-by-step explanation:

A company produces x units of a product per month.

The total cost represents by the function C(x).

$C(x)=300x+250$

The total revenue represents by the function R(x).

$R(x)=-0.5x^2+800x-100$

The profit is the difference between revenue and cost.

$P(x)=R(x)-C(x)$

$P(x)=-0.5x^2+800x-100-(300x+250)$

$P(x)=-0.5x^2+800x-100-300x-250$

Combine like terms.

$P(x)=-0.5x^2+(800x-300x)+(-100-250)$

$P(x)=-0.5x^2+500x-350$

Therefore, the total profit P(x) or the month is $P(x)=-0.5x^2+500x-350$ .

5 0

3 years ago