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3 years ago

(A) find F(x) for the indicated values of x, if possible

Mathematics

1 answer:

dem82 [27]3 years ago

8 0

Answer:

A) The indicated values of F(x) for x=-3 and x=5 are $F(-3)=-27$ and $F(5)=125$

B) The domain of f is the set of all real numbers

Step-by-step explanation:

Given that the function F is defined by

$F(x)=x^3$ for x=-3,5

A) To find F(x) for the indicated values of x :

Given $F(x)=x^3$ for x=-3,5

Put x=-3 in the given function

$F(-3)=(-3)^3$

$=(-3)\times (-3)\times (-3)$

$=-27$

Therefore $F(-3)=-27$

Put x=5 in the given function

$F(5)=(5)^3$

$=(5)\times (5)\times (5)$

$=125$

Therefore $F(5)=125$

The indicated values of F(x) for x=-3 and x=5 are $F(-3)=-27$ and $F(5)=125$

B) To find the domain of f :

The domain of the f in the given expression is the set of all real numbers except where the expression $x^3$ is undefined. In this case, there is no real number that makes the expression undefined.

The domain of f is the set of all real numbers

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Two cities A and B are 1400km apart and lie on the same N-S line. The latitude of city A is 23 Degrees. What is the latitude of

erica [24]

Answer:

${\theta}=12.53 degrees$ ≈13degrees

Step-by-step explanation:

It is given that Two cities A and B are 1400km apart and lie on the same N-S line. The latitude of city A is 23 Degrees. Then,

Using the formula, $S=r{\theta}$ where s is the distance between the two cities and r is the radius of the earth,thus substituting the values, we get

$1400=6400{\theta}$

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3 years ago

the vertex of this parabola is at (2,-4). when the y-value us -3, the x-value is -3. what is the coefficient of the squared term

alex41 [277]

Answer:

The coefficient of the squared term is 1/25.

Step-by-step explanation:

We are given that the vertex of a parabola is at (2, -4). We also know that y = -3 when x = -3.

And we want to determine the coefficient of the squared term of the equation.

Since we are given the vertex, we can use the vertex form of the quadratic:

$\displaystyle y = a(x-h)^2+k$

Where (h, k) is the vertex and a is the leading coefficient. The leading coefficient is also the coefficient of the squared term, so we simply need to find the value of a.

Since the vertex is at (2, -4), h = 2 and k = -4. Substitute:

$\displaystyle y = a(x-2)^2-4$