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IRINA_888 [86]
3 years ago
15

(A) find F(x) for the indicated values of x, if possible

Mathematics
1 answer:
dem82 [27]3 years ago
8 0

Answer:

A) The indicated values of F(x) for x=-3 and x=5 are F(-3)=-27  and F(5)=125

B) The domain of f is the set of all real numbers

Step-by-step explanation:

Given that the function F is defined by

F(x)=x^3 for x=-3,5

A) To find F(x) for the indicated values of x :

Given F(x)=x^3 for x=-3,5

  • Put x=-3 in the given function

F(-3)=(-3)^3

=(-3)\times (-3)\times (-3)

=-27

Therefore F(-3)=-27

  • Put x=5 in the given function

F(5)=(5)^3

=(5)\times (5)\times (5)

=125

Therefore F(5)=125

The indicated values of F(x) for x=-3 and x=5 are F(-3)=-27  and F(5)=125

B) To find the domain of f :

The domain of the f in the given expression is the set of all real numbers except where the expression x^3 is undefined. In this case, there is no real number that makes the expression undefined.

The domain of f is the set of all real numbers

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What is the trigonometric ratio for sin Z ?
Schach [20]

In all right triangles, the ratio between a leg and the hypothenuse is the sine of the angle opposite to the leg.

So, in your case, we have

\sin(Z) = \dfrac{XY}{XZ}

In order to find XY, we have

XY = \sqrt{XZ^2-YZ^2} = \sqrt{1600-1024}=\sqrt{576} = 24

So, the ratio for the sine is

\sin(Z) = \dfrac{XY}{XZ} = \dfrac{24}{40} = \dfrac{3}{5}

6 0
3 years ago
What is the longest line segment that can be drawn in a right rectangular prism that is 14cm​ long, 13cm​ wide, and 11cm​ tall?
vlabodo [156]

The longest line segment that can be drawn in a right rectangular prism that is 14cm long, 13cm wide and 11cm tall is 19.1cm.

<h3>What is a right rectangular prism?</h3>

A right rectangular prism is a three dimensional solid shape formed by 6 rectangles.

it is also called the cuboid.

Analysis:

The diagonal of the face of the prism with dimensions 14cm long and 13cm wide is the longest line segment that can be drawn.

Since rectangles have 90° on each vertex, we can use Pythagoras theorem to calculate for the length of the diagonal.

(diagonal)^{2} = (length)^{2} + (width)^{2}

(diagonal)^{2} = (14)^{2} + (13)^{2}

                 = 196 + 169 = 365

 (diagonal)^{2} = 365

diagonal = \sqrt{365} = 19.1cm

In conclusion, the length of the longest diameter is 19.1cm

Learn more about Right rectangular prism: brainly.com/question/3317747

#SPJ1

               

4 0
2 years ago
I really need help on this 8th grade geometry
wariber [46]
The answer is 39 degrees <span />
5 0
3 years ago
Dewan’s bank account balance is -$16.75. He deposits checks totaling $23.59. What is his new balance?
Brilliant_brown [7]

Answer:

b because 23.59+ (-16.75) = 6.84

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find x, y, and z<br><br> x = 39<br> x = 29<br> y = 61<br> y = 29<br> z = 61<br> z = 29
nikdorinn [45]

answer:

x = 29

y = 29

z = 61

step-by-step explanation:

all angles in a triangle must equal 180 degrees.

we were already given the angle degree of 61 degrees so we must include that in our formula to determine the degree of y.

the line in the middle already gives us two more angles because they both are 90 degrees for being a perfect quarter turn.

so to figure out y,

we must add 61+90 and then subtract the sum of that from 180.

so, 61+90 = 150 and 180-151 = 29

therefore,

we can conclude that y = 29

now, to determine the degrees of x and z we do the same thing.

we already know one angle equals 90 degrees.

180-90 = 90

that concludes that x and z must have a sum of 90.

if we use our choices,

39+61 = 100 (no)

39+29 = 68 (no)

29+61 = 90 (CORRECT)

29+29 = 28 (no)

<em>therefore, x = 29 and z = 61</em>

<em></em>

<em>so, in total :</em>

<em>x = 29</em>

<em>y = 29</em>

<em>z = 61</em>

<em></em>

<em>hope this helps :)   </em>

<em>-audrey <3 </em>

5 0
3 years ago
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