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2 years ago

If there are 5,280 feet in a mile, how many feet are in 2.6 miles?

Mathematics

2 answers:

Katen [24]2 years ago

8 0

The correct answer is 13,728

Hope this helps!

tatuchka [14]2 years ago

8 0

13728 is your answer

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Which equation represents the graph shown?

gtnhenbr [62]

(0,2)and (3,-2)
slope = (2+2)/(0-3) = -4/3
y intercept b = 2

equation
y = -4/3 x + 2

Answer is A
y = -4/3 x + 2

3 0

3 years ago

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So could someone help me on this

LenaWriter [7]

Answer:

B. -6

Step-by-step explanation:

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2 years ago

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Please help i’m stuck in this and don’t know what to do

Sergio039 [100]

4 unit rate is 124. 5 unit rate is 16 6 unit rate is 60

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2 years ago

A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2

andrey2020 [161]

Answer:

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

Step-by-step explanation:

Consider the provided matrix.

$v_1=\begin{bmatrix}-3\\1 \end{bmatrix}$

$v_2=\begin{bmatrix}-1\\1 \end{bmatrix}$

$\lambda_1=4, \lambda_2=2$

The general solution of the equation $x'=Ax$

$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

Substitute the respective values we get:

$x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

Substitute initial condition $x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}$

$\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}$

Reduce matrix to reduced row echelon form.

$\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}$

Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

$x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

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2 years ago

If Andy had an ending balance of $5600 and Charlie had an ending balance of $5624.32, what is the difference in their account ba

MakcuM [25]

The answer is 24.32 is the difference

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2 years ago

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