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adelina 88 [10]
3 years ago
9

I will give Brainiest if you are right

Mathematics
1 answer:
Tpy6a [65]3 years ago
8 0

Answer:

d) $7.82

Step-by-step explanation:

just multiply the 2 numbers

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The ratio of the side length of a square to the square's perimeter is always 1 to 4.
makvit [3.9K]

Answer:

Side length of square (inches): 1 ,2, 4, 7

Perimeter of square (inches). : 4, 8, 16, 28

Step-by-step explanation:

Ratio is 1:4 (S:P).

So:

#:8, #=2. This is because 2/8 and 1/4 both = 0.25.

#:16, #=4. 4/16=0.25

7:#, #=28. 4x7=28, 7/28=0.25

Hope that helps

7 0
2 years ago
Use substitution to solve the system.<br> -5x + 3y = 19<br> x = 3y - 11
telo118 [61]

Answer:

x = -2

y = 3

Step-by-step explanation:

-5x + 3y = 19

x = 3y - 11

-5x + 3y = 19

-5(3y - 11) + 3y = 19

-15y + 55 + 3y = 19

-15y + 3y + 55 = 19

-12y + 55 = 19

-12y = 19 - 55

-12y = -36

y = -36/-12

<u>y = 3</u>

x = 3y - 11

x = 3(3) - 11

x = 9 - 11

<u>x = -2</u>

5 0
3 years ago
UR awesome Samantha ;-)
Andreyy89

multiply by 4 for each number

5*4=20

20*4= 80

80*4=320

Answer is 320

7 0
3 years ago
Read 2 more answers
How many solutions exist for the given equation?
EleoNora [17]
The answer would be one because:

6 0
4 years ago
Read 2 more answers
Lee read 1/6 of book on monday and another 1/3 of it on tuesday ,he took another 4 days to finish reading the book he read the s
Mkey [24]

Answer:

1/8

Step-by-step explanation:

Let

The total fraction of the book read = 1

The remaining 4 days be represented as= x

Hence:

1 = Fraction of book read on Monday + Fraction of the book read on Tuesday + Fraction of the book on the remaining 4 days

1 = 1/6+ 1/3 + x

x = 1 - (1/6+ 1/3)

x = 1 - (1 + 2/6)

x = 1 - (3/6)

x = 1 - 1/2

x = 1/2

The fraction of the book read in 4 days = 1/2

To calculate the fraction of the book read on each of the days, since he read the same number of pages on each of the days we have:

1/2 ÷ 4 days

= 1/2 × 1/4

= 1/8

Therefore, the fraction of the book that was read on each of the 4 days is 1/8

4 0
3 years ago
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