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4 years ago

In polar coordinates, the axis determined by theta=0 is called ?

Mathematics

2 answers:

forsale [732]4 years ago

6 0

polar according to APEX for whatever reason

melisa1 [442]4 years ago

4 0

In polar coordinates, the axis determined by theta=0 is called the positive x-axis or horizontal axis.

To add, in mathematics, the polar coordinate system is a two-dimensional coordinate system in which each point on a plane is determined by a distance from a reference point and an angle from a reference direction.

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The value of 110 coins, consisting of dimes and quarters, is $20.30. how many of each kind of coin are there?

deff fn [24]

D + q = 110......d = 110 - q
0.10d + 0.25q = 20.30

0.10(110 - q) + 0.25q = 20.30
11 - 0.10q + 0.25q = 20.30
-0.10q + 0.25q = 20.30 - 11
0.15q = 9.30
q = 9.30/0.15
q = 62 <==== there are 62 quarters

d = 110 - q
d = 110 - 62
d = 48 <==== there are 48 dimes

6 0

3 years ago

the ratio of the sides of a certain triangle is 2:7:8 if the longest side of the triangle is 40cm how long are the other two sid

Zigmanuir [339]

The length of the other two sides is 10 and 35 respectively.

<h3>What is a ratio?</h3>

A ratio is a quantitative relation showing the comparison between two or more numbers. It can also be written in the fractional form where the first part is the numerator and the second part is called the denominator.

From the given information:

The sides of the triangle = 2:7:8
The total sides of the triangle = 2+7+8 = 17

We are being told that the longest side is the triangle is equal to 40.

i.e.

$\mathbf{\to\dfrac{8}{17}\times x = 40}$

$\mathbf{x = 40 \div \dfrac{8}{17}}$

$\mathbf{x = 40 \times \dfrac{17}{8}}$

x = 85

Now for the other two sides 2 and 7, their length is as follows.

$\mathbf{\dfrac{2}{17}\times 85 = 10}$

$\mathbf{\dfrac{7}{17}\times 85 = 35}$

Therefore, we can conclude that the length of the other two sides is 10 and 35 respectively.

Learn more about ratios here:

brainly.com/question/2328454

3 0

2 years ago

Prove the polynomial identity.

Ronch [10]

Answer:

The answer to your question is: 2, 4, 5, 1 , 3

Step-by-step explanation:

The first line is the second

(3x² - 6)² - (3x²)² = 36(1 - x)(1 + 1)

The second line is the forth

9x⁴ - 36x² + 36x² - 9x⁴ = 36(1 - x)(1 + x)

The next line is the fifth

36 - 36x² = 36(1 - x)(1 + x)

The next line is the first

36(1 - x²) = 36(1 - x)(1 + x)

The last line is the third

36(1 - x)(1 + x) = 36(1 - x)(1 + x)

3 0

3 years ago

Read 2 more answers

Let A and B be nxn matrices such that AB is singular prove that either A or Bis singular

Alex_Xolod [135]

$\det(\mathbf{AB})=\det\mathbf A\times\det\mathbf B$

Because $\mathbf{AB}$ is singular, we have

$\det(\mathbf{AB})=0$

from which it follows that either $\det\mathbf A=0$ or $\det\mathbf B=0$ .

4 0

3 years ago

HELP I NEED THIS NOW!!!!

borishaifa [10]

Answer:

So, The area of trapezoid = 4.413 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and m∠NMK = 65° , OT = R

So, m∠MNP = 180° - 65° = 115° ⇒ supplementary interior angles.

Join ON ⇒ ΔOSN is a right triangle at S.

And NP, NM are tangents to the circle

So, ON bisects the angle ∠MNP = ∠MNS

∠ONS = (∠MNS)/2 = 115/2 = 57.5°

So, tan (∠ONS) = OS/NS = R/(NS)

NS = R/tan (∠ONS)=R/(tan 57.5°) ≈ 0.637 R

∴ NP = 2 * NS = 1.274 R

Construct: a line parallel to ST from N to line MK

let the intersection point be Q ⇒ NQ = 2R

So, Δ NQM is a right triangle at Q

tan (∠NMQ) = tan 65 = NQ/MQ

MQ = NQ/(tan 65)=2R/tan 65 ≈ 0.932 R

∴ MK = 2 MT = 2 (MQ + QT) ⇒ QT = NS

= 2 (MQ + NS ) = 2( 0.932 R + 0.637 R) = 2 * 1.569 R

∴ MK = 3.139 R

Now, area of trapezoid = height × (sum of parallel sides/ 2)

Area = ST * (NP + MK)/2

= 2R * (1.274 R + 3.139 R) / 2

= 2R * 4.413 R /2

= 4.413 R²

So, The area of trapezoid = 4.413 R²

5 0

3 years ago