All categories

3 years ago

Jeremy washes 3/8 of the plates from dinner if 16 plates were used how many plates did Jeremy wash

Mathematics

1 answer:

WITCHER [35]3 years ago

4 0

Answer:6

Step-by-step explanation: we simplify 1/16 by dividing it in half, so half of 16 is 8. And according to the question there were 3/8 washed plates. So we reverse that by multiplying the fraction by 2. 3/8•2= 6/16.

You might be interested in

Which expression is equivalent to (3x−2)(x+6)

NISA [10]

Answer: 3x^2+16x-12

Step-by-step explanation:

5 0

3 years ago

Kim paid

Anna11 [10]

Answer:

Sherri paid the most

Step-by-step explanation:

35% > 33%

3 0

3 years ago

Read 2 more answers

If he changed would you ever get back with him I think he truly means what he says he’s really hurt and always says he feels the

alukav5142 [94]

The answer is D. Angles 2 and 3

5 0

3 years ago

Which set is ordered greatest to least?

weeeeeb [17]

16% = 0.16

1/6 = 0.16666

1.6x10^6 = 1600000

0.166 = 0.166

order from greatest to least:

1.6x10^6, 1/6, 0.166, 16%

Answer is D

6 0

3 years ago

Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

7 0

3 years ago